Week 1 – SS1 First Term General Mathematics Notes

SS1 GENERAL MATHEMATICS SCHEME OF WORK FOR FIRST TERM
WEEK[S] TOPIC

1. Revision of Jss3 work and basic operations of integers; addition, subtraction, multiplication and division.
2. Number Bases; [a] Conversion from one base number to base ten. [b] Conversion of decimal fraction [bicimals] in one base to base ten. [c] Conversion of numbers from one base to another.
3. [a] Addition, subtraction, multiplication and division of number bases . [b] Application of number bases to computer programming.
4. Concept of Modular Arithmetic; Addition, subtraction, multiplication and division of operations of modular arithmetic.
5. Standard form and Approximation
6. Indices; [a]Application of laws of indices. [b] Negative, zero and fractional indices.
7. Reviewof first half term and periodic test
   
8. Logarithms of numbers greater than 1 [whole number]→ use of logarithm table for multiplication and division of numbers.
   
9. Logarithms CTD; [a] calculations involving powers and roots. [b] Relationship between indices and logarithms.
   
10. [a] simple equation and variation. [b] Change of subject of formulae. [c] Type of variation; direct, inverse, joint and partial variation. [d] Applicationof variation to practical problems.
    
11. Revision.
    
12. Examination.
    
13. Examination
    

    REFERENCE BOOKS
    

• MAN MATHEMATICS FOR SENIOR SECONDARY SCHOOLS 1
  
• ESSENTIAL MATHEMATICS FOR SENIOR SECONDARY SCHOOLS 1 BY A.J.S OLUWASANMI
  
• NEW GENERAL MATHEMATICS FOR SENIOR SECONDARY SCHOOL 1 BY M.F.MACRAE ETAL                                                    
  

  Week 1.
  REVISION AND BASIC OPERATIONS OF INTEGER
  RULES OF DIVISIBILITY TEST
  A number is divisible by:

  • 2: if the last digit of the number is even or zero.
  • 3: if the sum of the digits is divisible by 3.
  • 4: if the number formed by the last 2 digits is divisible by 4.
  • 5: if the numbers end in 0 or 5.
  • 6: if the number is divisible by both 2and 3.
  • 7: no rule to it yet.
  • 8: if the number formed by the last three digits of the numbers is divisible by 8.
  • 9: if the sum of the digits is divisible by 9 and 3.
  • 10: if the last digit is zero.
  • 11: if the sum of the digits in the odd positions is equal to the sum of digits in the even positions or difference is a multiple of 11.

    DIVISIBILITY test is a rule for determining whether one whole number is divisible by another.
    EXAMPLE
    Determine whether7168 is divisible by2, 3, 4,5,6,8,9,10 and 11
    SOLUTION
    7168 Is not divisible by 3, 5, 6, 9, 10 and 11. But 2 because the last digit is even, 4 since the last twodigits is divisible by 4. 8 since the last three digit is divisible by 8.
    EXAMPLE
    Which number is divisible by 35120?
    SOLUTION
    35120 is divisible by 2,4,5,8and 10.
    2 can divide it since it end with zero, divisible by 4, since the last two digit 20 is divisible by 4, 5 since it end with zero, 8 since the last digit 120 is divisible by 8. 10 since the last digit is zero.
    EXAMPLE
    Determine whether 24739 is divisible by 11?
    SOLUTION
    24739→sum of digit in odd position 2+7+9=18, sum of digit in even position 4+3=7. Thedifference18-7=11. Then 11 is divisible by 11 and a multiple of 11.
    CLASS WORK
    

  Identify the following numbers that can be divisible by 2,4 ,5 , 6,8, 9.
  a.3591 b. 2408 c. 7700 d. 18054 e.2032 f. 1827 g.23624 h. 468
  INTEGERS: integers are whole numberse.g. 1,3, 6,7,9. etc. not 1.5,,5.
  SIMPLIFY: Simplify is to make easier to do or understand.
  EVALUATE:To Evaluate is to form a value or quality after thinking , resolving or working a problem.
  EXAMPLE
  Find the sum of the following number :
  

1. 961,86 and 422. B. 4312,504,614 and 24
   

   Solution
   

1. 961 b. 4 3 1 2
   

(a) 8 6 +₊ 5 0 4
4 2 2 6 1 4
14 6 9 5 4 3 0
Subtract 287 from 306.
Solution
3 0 6
– 2 8 7
0 1 9
Find the product of 452 and 219
SOLUTION
452
X 219                                     4 0 6 8
+ 452
904
98988
Find the value of the following:

1. 8(+7). b. 5 (9). (C )
   

    Solution
   

   1. 8 (+7 )= 87 =+1
      
   2. -5(-9)=-5+9 =+4
      
   3. = =9.6
      

   ASSESSMENT: The students are to work the following questions:
   

   1. Find the product of the following numbers:
      
      1. 2184×11 b. 5412×99 c. 217×405
         
   2. Subtract the following numbers:
      
      1. 23 from 36 b. 94 from 104
         
   3. Find the values of :
      
      1. 336÷4 b. 867÷17 c. 1848÷12 d. (-18)÷(-3) e. -25÷4
         
   4. find the values of the following:
      

       

   5. b.