SCHEME OF WORK FOR J SS 2

WEEK 1    REVIEW OF FIRST TERM WORK, EXPANDING AND FACTORIZING ALGEBRAIC EXPRESSIONS, SOLVING OF QUADRATIC EQUATIONS.
WEEK 2 WORD PROBLEMS ON ALGEBRAIC FRACTION
WEEK 3 LINEAR INEQUALITIES
WEEK 4 LINEAR INEQUALITIES IN ONE VARIABLE, GRAPHICAL PRESENTATIONS OF SOLUTION OF LINEAR INEQUALITIES.
WEEK 5 GRAPHS OF LINEAR EQUATIONS IN TWO VARIABLES
WEEK 6 PLANE FIGURES OR SHAPES, IDENTIFICATION OF PLANE SHAPES WITH THEIR PROPERTIES.
WEEK 7 REVIEW OF THE FIRST HALF TERMS’S AND PERIODIC TEST
WEEK 8 SCALE DRAWING OF LENGTH AND DISTANCES
WEEK 9 QUANTITATIVE APTITUDE PROBLEMS
WEEK 10 REVISION OF SECOND HALF TERM’S WORK.
WEEK 11 REVISION
WEEK 12 EXAMINATION.

 WEEK 2 WORD PROBLEM LEADING TO ALGEBRAIC EXPRESSION
Sometimes you may be asked to solve problem given in words. To do this you need to convert the words into an algebraic equation and then solve it. The following points will show you what to do.
a.    Read the equation carefully and then decide what the unknown number is
b.    Where necessary, change all the unit of measurement to the same unit
c.    Use a letter to represent the unknown
d.    Use the information provided to write the required equation
e.    Solve the equation as usual
f.    Use the solution obtained to answer the questions in words
g.    You can check your answer as usual.
Example1: Think of a number, add 5 to it and multiply the result by 3, the answer is 36. What is the number?
Example 2:The sum of a number and 9 is multiplied by -2 and the answer is -8. Find the number
Example 3: The smallest of three consecutive odd number is n, if their sum is 27. Find the three numbers.
Solution:
Note the rules above. Follow the steps.
1.    Let the number be X, add 5 to it, = X + 5, multiple by 3
    3(X+5), the answer is 36
    Open the bracket 3(X+5) = 36 [use the 3 to multiply the equation]
    3x + 15 = 36 [subtract 15 from both side]
    3X + 15 – 15 = 36 – 15
    3X = 21[divide both side by 3
    3X/3 = 21/3
    X = 7
    Check
    3(7+5)
    3X12=36

 2.    Let X be the number, X + 9, multiply by -2,
    -2(X + 9), the answer is -8
    -2(X + 9) = -8 [open the bracket]
    -2X -18 = -8
    Collect the like term
    -2X = -8 + 18 [the sign we change to positive]
    -2x = 10
    Divide both sides by -2
    -2X/-2 = 10/-2
    X = -5
Check
-2(-5+9)
-2(+4) = -8
3.    Let the first number be n, second number to be n+2, third number be n+4.
    Note that odd number are 1, 3, 5, 7, the difference between each number is 2.
    N+N+2+N+4 = 27
    Collect the like term
    3N + 6 = 27 [subtract 6 from both sides]
    3N = 27 – 6
    3N = 21
    Divide both sides by 3
    3N/3 = 21/3
    N = 7
    N =7, N+2= 7+2 = 9, N + 4 = 7 + 4 = 11
    Therefore the consecutive numbers are 7, 9, and 11

 EVAULATION: Translate the following statement into algebraic equations and then solve them

  1. Think of a number, and 5, the result is 10. What is the number?
  2. Two market women shared a basket full of oranges in order to sell them. The share of the first woman is twice the other. If there are 300 oranges in the basket. What is the share of each woman?
  3. The sum of three consecutive even numbers is 60. Find the numbers.

 ASSIGNMENT: PAGE 159 EXERCISE 13.5 NO 4, 6,8,15, AND 18
    

 

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