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Reciprocals Questions
1. Use reciprocal, square and square root tables to evaluate, to 4 significant figures, the expression. (3 mks)
1. Use reciprocal table to evaluate giving your answer to three significant figures.
10 – 3
0.834 129.64
2. Find the reciprocals of the numbers 807 and 0.0591;
Hence evaluate 5 + 4
807 0.0591
3. Use reciprocal tables to find the value of:
2 + 5
0. 6638 0.833
4. Find without using a calculator, the value of :
12 0.0625 – 12.4 ÷ 0.4 x 3
1/8 of 2.56 + 8.68
5. Use tables of cubes, cube roots and reciprocal to find the value of:-
4 + 5
(8.68)³ 34.46
6. Determine the value of a for which 1 + 1 = 1
127 11.5 a Use mathematical tables only
7. Use tables of squares, square roots and reciprocals only to find the value of x correct
to 4 significant figures:
8. Use reciprocal tables to find the value of
9. Use tables of reciprocals only to work out;
3 + 13
0.6735 0.156
10. Using tables of squares, cube roots and reciprocals find the value of x.
1 = 1 – 1
x 0.002593 1.28
Reciprocals Answers
1 |
4.3509 | B1
B1
B1 | reciprocal
square
square root |
2. 10 1 – 3 1
0.834 129.64
(10 x 1.199) – (3 x 0.007713)
11.99 – 0.923139
11.966861
12.0
3. 807 0.001239
0.0591 16.92
5(0.001239) + 4(16.92)
= 67.69
4. 1/3
2 x 1.5065 + 5 x 1.2004
1/3 (3.013 + 6.002) (0.3333)
= 9.015 x 0.3333
= 3.005 (3 dp)
5. 12 x 0.25 – 12.4 ÷ 0.4 x 3
⅛ of 2.56 + 8.68
3 – 31 x 3
0.32 + 8.68
-90
9
= -10
6. 1/3
4 + 5
(8.68)3 34.46
4 + (0.1451)1/3
653.97
4(0.1529) + 0.5255
0.6116 + 0.5255 = 1.1371
7. 1 = 0.007874 + 0.0869
a
= 0.9483
a = 10.55
8. 3.5932 = 12.91
1 + 2 1
1.291 x 10 5.26 x 10-1
= (0.7746 x 10-1) +290.1901 x 10)
= 0.07746
+ 3.802
3.87946
3.87946 = 3.879
= 1.9695
= 1.970(4s.f)
9. No s.f rec
0.6638 6.638 x 10-1 0.1500 x 10 = 1.5000
0.833 8.33 x 10-1 0.1200 x 10 = 1.200
= 1/3 (2 (105) + (1.2))
= 1/3 (3 + 6)
= 1/3 x 9 = 3
10. 3×1.485 + 13×6.410
= 4.455 + 83.33
= 87.785
ALT
30/6.735 + 130/1.56 = 30 x 0.1485 + 130x 0.641
= 4.455 + 83.33
= 87.785