{"id":4076,"date":"2023-10-06T09:27:03","date_gmt":"2023-10-06T09:27:03","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=4076"},"modified":"2023-10-06T09:30:04","modified_gmt":"2023-10-06T09:30:04","slug":"week-1-and-2-ss3-second-term-mathematics-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-1-and-2-ss3-second-term-mathematics-notes\/","title":{"rendered":"Week 1 and 2 – SS3 Second Term Mathematics Notes"},"content":{"rendered":"

SECOND TERM E-LEARNING NOTE
\n<\/strong>
\n\u00a0SUBJECT: MATHEMATICS\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0CLASS: SS 3
\n<\/strong>
\n\u00a0SCHEME OF WORK
\n<\/strong>
\n\u00a0WEEK\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0TOPIC<\/p>\n

    \n
  1. Calculation on interest on bonds and debentures using logarithm table and problems on taxes and value added tax.\n<\/li>\n
  2. Coordinate Geometry of straight line: Cartesian coordinate graphs, distance between two points, midpoint of the line joining two points.\n<\/li>\n
  3. Coordinate Geometry of straight lines: Gradient and Intercepts of a line, angle between two intersecting straight lines and application.\n<\/li>\n
  4. Differentiation of algebraic functions: meaning of differentiation, differentiation from first principle and standard derivatives of some basic functions.\n<\/li>\n
  5. Differentiation of algebraic functions: Basic rules of differentiation such as sum and difference, product rule, quotient rule and maximal and minimum application.\n<\/li>\n
  6. Integration and evaluation of simple algebraic functions: Definition, method of integration: substitution, partial fraction and integration by parts, area under the curve and use of Simpson’s rule.\n<\/li>\n<\/ol>\n
      \n
    1. \n
      \u2013 12. Revision and mock examination.\n<\/div>\n

      \u00a0<\/li>\n<\/ol>\n

      REFERENCE TEXT
      \n<\/strong><\/p>\n

        \n
      • New General Mathematics for SS book 3 by J.B Channon\n<\/li>\n
      • Essential Mathematics for SS book 3\n<\/li>\n
      • Mathematics Exam Focus\n<\/li>\n
      • Waec and Jamb past Questions\n<\/li>\n<\/ul>\n

        \u00a0
        \n\u00a0WEEK ONE
        \n\t\t\t<\/strong><\/p>\n

          \n
        • Calculation on interest on bonds and debentures using logarithm table\n<\/li>\n
        • Problems on taxes and value added tax.\n<\/li>\n<\/ul>\n

          \u00a0WEEK TWO
          \n\t\t\t<\/strong><\/p>\n

            \n
          • Coordinate Geometry of straight line: Cartesian coordinate graphs\n<\/li>\n
          • distance between two points\n<\/li>\n
          • midpoint of the line joining two points\n<\/li>\n
          • Coordinate Geometry of Straight line:\n<\/li>\n
          • \n
            Cartesian coordinate graph:\n<\/div>\n

            \u00a0Distance between two lines:
            \n<\/strong>I<\/strong>n the figure below, the coordinates of the points A and B are (x1<\/sub>, y1<\/sub>) and (x2<\/sub>, y2<\/sub>), respectively. Let the length of AB be l.
            \n\"\"\/\"\"\/y
            \n\"\"\/ B(x2<\/sub>, y2<\/sub>)<\/p>\n

            \u00a0l
            \n y2<\/sub> \u2013 y1<\/sub><\/p>\n

            \u00a0 A(x1<\/sub>, y1<\/sub>) x2<\/sub> \u2013 x2 <\/sub> C
            \n\"\"\/ X
            \nUsing Pythagoras theorem:
            \nAB2<\/sup> = AC2<\/sup> + BC2<\/sup>
            \n\t\t\t\t l2<\/sup> =(x2<\/sub> \u2013 x1<\/sub>)2<\/sup> + (y2<\/sub> \u2013 y1<\/sub>)2<\/sup>
            \n\t\t\t\tl = \u221a(x2<\/sub> \u2013 x1<\/sub>)2<\/sup> + (y2<\/sub> \u2013 y1<\/sub>)2<\/sup>
            \n\t\t\t\t\t<\/strong>
            \n\u00a0Example:
            \n<\/strong>Find the distance between the each pair of points: a. (3, 4) and (1, 2) b. (3, – 3) and (- 2, 5)
            \nSolution:
            \nUsing l =\u221a(x2<\/sub> \u2013 x1<\/sub>)2<\/sup> + (y2<\/sub> \u2013 y1<\/sub>)2<\/sup>\n\t\t\t\t<\/li>\n<\/ul>\n

              \n
            1. \n
              l = \u221a(3 \u2013 1)2<\/sup> + (4 \u2013 2)2<\/sup>\n\t\t\t\t<\/div>\n

              l = \u221a22<\/sup> + 22
              \n<\/sup>l = \u221a8 = 2\u221a2 units<\/p>\n

              \u00a0<\/li>\n

            2. \n
              l = \u221a(3 \u2013 (-2)2<\/sup> + (-3 \u2013 5)2<\/sup>\n\t\t\t\t<\/div>\n

              = \u221a52<\/sup> + (-8)2<\/sup>
              \n\t\t\t\t= \u221a25 + 64 = \u221a89 = 9.43 units\n<\/li>\n<\/ol>\n

              \u00a0Evaluation<\/strong>: Find the distance between the points in each of the following pairs leaving your answers in surd form: 1. (-2, – 5) and (3, – 6) 2. (- 3, 4) and (- 1, 2)<\/p>\n

              \u00a0Mid-point of a line:
              \n<\/strong>The mid-point of the line joining two points: <\/p>\n

              \u00a0\"\"\/y
              \n\"\"\/ B(x2<\/sub>, y2<\/sub>)<\/p>\n

              \u00a0 y2<\/sub> – y
              \n\"\"\/\"\"\/ M(x, y) D
              \nx2<\/sub> \u2013x
              \n y \u2013 y1<\/sub><\/p>\n

              \u00a0 A(x1<\/sub>, y1<\/sub>) x \u2013 x1 <\/sub> N C
              \n\"\"\/ X
              \n Triangle MAN and BMD are congruent, so AM = MD and BD = MN
              \n x \u2013 x1<\/sub> = x2<\/sub> \u2013 x y \u2013 y1<\/sub> = y2<\/sub> \u2013 y
              \n x + x = x2<\/sub> + x1<\/sub> y + y = y2<\/sub> + y1<\/sub>
              \n\t\t 2x = x2<\/sub> + x1<\/sub> 2y = y2<\/sub> + y1
              \n<\/sub>x= x2<\/sub> + x1<\/sub> y = y2<\/sub> + y1<\/sub>
              \n\t\t\t<\/strong> 2 2
              \n<\/strong>\"\"\/\"\"\/Hence, the mid-point<\/strong> of a straight line joining two is x2<\/sub> + x1<\/sub> ,y2<\/sub> + y1<\/sub>
              \n\t\t\t<\/strong> 2 2
              \n<\/strong>Example<\/strong>: Find the coordinates of the mid-point of the line joining the following pairs of points.<\/p>\n

                \n
              1. \n
                (3, 4) and (1, 2) b. (2, 5) and ( – 3, 6)\n<\/div>\n

                \"\"\/Solution:\n<\/li>\n<\/ol>\n

                Mid-point = x2<\/sub> + x1<\/sub> ,y2<\/sub> + y1<\/sub>
                \n\t\t\t<\/strong> 2 2
                \n<\/strong><\/p>\n

                  \n
                1. \n
                  \"\"\/Mid-point = 1 + 3 , 4 + 2 = (2, 3)\n<\/div>\n

                  2 2\n<\/li>\n

                2. \"\"\/\"\"\/Mid-point = – 3 + 2 , 6+ 5 = – 1 , 11\n\t\t\t<\/li>\n<\/ol>\n

                  2 2 2 2
                  \nEvaluation:<\/strong> Find the coordinates of the mid-point of the line joining the following pairs of points.<\/p>\n

                    \n
                  1. (- 2 , – 5) and (3, – 6) b. (3, 4) and ( – 1, – 2)\n<\/li>\n<\/ol>\n

                    \u00a0General Evaluation
                    \n<\/strong><\/p>\n

                      \n
                    1. Find the distance between the points in each of the following pairs leaving your answers in surd form: 1. (7, 2) and (1, 6)\n<\/li>\n
                    2. What is the value of r if the distance between the points (4, 2) and (1, r) is 3 units?\n<\/li>\n
                    3. Find the coordinates of the mid-point (-3, -2) and (-7, – 4)\n<\/li>\n<\/ol>\n

                      \u00a0Reading Assignment: NGM for SS 3 Chapter 9 <\/strong>page 77 \u2013 78,
                      \n\t\t\t<\/strong>\u00a0\u00a0\u00a0\u00a0
                      \nWeekend Assignment:
                      \n<\/strong><\/p>\n

                        \n
                      1. Find the value of \u03b12<\/sup> + \u03b22<\/sup> if \u03b1 + \u03b2 = 2 and the distance between the points (1, \u03b1) and (\u03b2, 1) is 3 units.\n<\/li>\n
                      2. The vertices of the triangle ABC are A (7, 7), B (- 4, 3) and C (2, – 5). Calculate the length of the longest side of triangle ABC.\n<\/li>\n
                      3. \n
                        Using the information in ‘2’ above, calculate the line AM, where M is the mid-point of the side opposite A.\n<\/div>\n

                        \t\t\t\t\u00a0<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

                        SECOND TERM E-LEARNING NOTE \u00a0SUBJECT: MATHEMATICS\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0CLASS: SS 3 \u00a0SCHEME OF WORK \u00a0WEEK\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0TOPIC Calculation on interest…<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,316],"tags":[],"class_list":["post-4076","post","type-post","status-publish","format-standard","hentry","category-posts","category-second-term-ss3-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/4076","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=4076"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/4076\/revisions"}],"predecessor-version":[{"id":4077,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/4076\/revisions\/4077"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=4076"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=4076"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=4076"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}