{"id":2897,"date":"2023-10-03T16:01:39","date_gmt":"2023-10-03T16:01:39","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=2897"},"modified":"2023-10-03T16:03:34","modified_gmt":"2023-10-03T16:03:34","slug":"week-8-ss2-first-term-mathematics-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-8-ss2-first-term-mathematics-notes\/","title":{"rendered":"Week 8 &#8211; SS2 First Term Mathematics Notes"},"content":{"rendered":"<p>\u00a0<strong>WEEK EIGHT<br \/>\n<\/strong><strong>TOPIC:  SIMULTANEOUS EQUATIONS<br \/>\n<\/strong><strong>CONTENT<br \/>\n<\/strong><\/p>\n<ul>\n<li>Solving Simultaneous Equations Involving One linear and One quadratic.\n<\/li>\n<li>Solving Simultaneous Equations Using Graphical Method\n<\/li>\n<\/ul>\n<p><strong>SIMULTANEOUS EQUATIONS INVOLVING ONE LINEAR AND ONE QUADRATIC<br \/>\n<\/strong>One of the equations is in linear form while the other is in quadratic form.<br \/>\n<strong>Note:<\/strong> One linear, one quadratic is only possible analytically using substitution method.<\/p>\n<p>\u00a0<strong>Examples:<br \/>\n<\/strong>1. Solve simultaneously for x and y (i.e. the points of their intersection)<br \/>\n\u00a0\u00a0\u00a0\u00a03x + y = 10 &amp; 2x<sup>2<\/sup> +y<sup>2<\/sup> = 19<br \/>\n<strong>Solution<br \/>\n<\/strong>3x + y = 10 &#8212;&#8212;&#8212;&#8211; eq 1<br \/>\n2x<sup>2<\/sup> + y<sup>2<\/sup> = 19 &#8212;&#8212;&#8212; eq 2<\/p>\n<p>\u00a0Make y the subject in eq 1 (linear equation)<br \/>\ny = 10 \u2013 3x &#8212;&#8212;&#8212;- eq 3<br \/>\nSubstitute eq 3 into eq 2<br \/>\n2x<sup>2<\/sup> + (10-3x) <sup>2<\/sup>   = 19<br \/>\n2x<sup>2<\/sup><sub>+ <\/sub>(10 \u2013 3x) (10 \u2013 3x) = 19<br \/>\n2x<sup>2<\/sup> + 100 \u2013 30x \u2013 30x + 9x<sup>2<\/sup> = 19<br \/>\n2x<sup>2<\/sup> + 9x<sup>2<\/sup> &#8211; 30x \u2013 30x + 100 \u2013 19 = 0<br \/>\n11x<sup>2<\/sup> &#8211; 60x + 81 = 0<br \/>\n11x<sup>2<\/sup> &#8211; 33x \u2013 27x + 81= 0<br \/>\n11x (x-3) \u2013 27 (x \u2013 3) = 0<br \/>\n(11x \u2013 27) (x \u2013 3) = 0<br \/>\n11x \u2013 27 = 0  or x-3 = 0<br \/>\n11x = 27 or  x = 3<br \/>\n\\ x = 27\/11   or 3<br \/>\nSubstitute the values of x into eq 3.<\/p>\n<p>\u00a0When x = 3<br \/>\ny = 10 \u2013 3(x)<br \/>\ny = 10 &#8211; 3(3)<br \/>\n y = 10 \u2013 9 = 1<\/p>\n<p>\u00a0When x =27\/11<br \/>\ny = 10 \u2013 3(27\/11)<br \/>\ny = 10 &#8211; 51\/11<br \/>\ny = 110 &#8211; 51<br \/>\n\t\t            11<br \/>\ny = 59\/11<br \/>\n\\w hen x = 3, y = 1<br \/>\nx = 27    ,   y =  59<br \/>\n\t\t                   11              11<br \/>\n\u00a0\u00a0\u00a0\u00a0<br \/>\n\u00a02. Solve the equations simultaneously 3x + 4y = 11   &amp;xy = 2<br \/>\n<strong>solution<\/strong><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a03x + 4y = 11      &#8212;&#8212;&#8211; eq 1<br \/>\n\u00a0\u00a0\u00a0\u00a0xy = 2        &#8212;&#8212;&#8211; eq 2<br \/>\n\u00a0\u00a0\u00a0\u00a0Make y the subject in eq 1<br \/>\n\u00a0\u00a0\u00a0\u00a04y  = 11 \u2013 3x<br \/>\ny =   11 \u2013 3x   \u2026\u2026\u2026\u2026   eq3<br \/>\n            4<br \/>\nsubstituteeq 3 into eq 2<br \/>\nx y = 2<br \/>\nx ( 11- 3x )  =  2<br \/>\n         4<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1601_Week8SS2Fi1.png\" alt=\"\"\/><br \/>\n\t\tx (11-3x) = 2&#215;4<br \/>\n11x \u2013 3x<sup>2<\/sup> = 8<br \/>\n-3x<sup>2<\/sup>   + 11x \u2013 8 = 0<br \/>\n-3x<sup>2<\/sup>   + 3x + 8x \u2013 8 = 0<br \/>\n-3x (x-1) +8 (x-1) = 0<br \/>\n(-3x + 8) (x-1) = 0<br \/>\n-3x + 8 = 0  or  x \u2013 1 = 0<br \/>\n 3x = 8  or  x = 1<br \/>\nx = 8\/3 or 1<br \/>\nSubstitute the values of x into eq 3<br \/>\ny =  11- 3x<br \/>\n\t\t           4<br \/>\nwhen x = 1<br \/>\ny =  11 \u2013 3(1)  = 11-3   =  8<br \/>\n\t\t             4               4          2<br \/>\n  y =  4<br \/>\nwhen x = 8\/3<br \/>\ny = 11 \u2013 3(8\/3)<br \/>\n\t\t            4<br \/>\ny =  33 \u2013 24  =  9      =    3<br \/>\n\t\t            12         12           4<br \/>\n\\ x = 1, y = 2<br \/>\nx = 8\/3, y = 3\/4.<\/p>\n<p>\u00a0<strong>Evaluation<br \/>\n<\/strong>Solve for x and y<br \/>\n1. 3x <sup>2 <\/sup> &#8211; 4y = -1                           2.  4x<sup>2<\/sup> + 9y<sup>2<\/sup> = 20<br \/>\n    2x \u2013 y = 1                                        2x \u2013 9y = -2<\/p>\n<p>\u00a0<strong>MORE EXAMPLES<br \/>\n<\/strong>Solve simultaneously for x and y.<br \/>\n3x \u2013 y = 3 &#8212;&#8212;&#8211; eq 1<br \/>\n9x<sup>2  <\/sup> &#8211; y <sup>2 <\/sup>= 45 &#8212;&#8212;&#8212; eq 2<br \/>\nSolution<br \/>\n<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1601_Week8SS2Fi2.png\" alt=\"\"\/>From eq 2<br \/>\n(3x)<sup>2<\/sup> &#8211; y <sup>2  <\/sup>= 45<br \/>\n(3x-y) (3x+y) = 45 &#8212;&#8212;&#8212;- eq 3<br \/>\nSubstitute eq 1 into eq 3<br \/>\n3 (3x + y) = 45<br \/>\n 3x + y = 15 \u2026\u2026\u2026\u2026\u2026..eq4<\/p>\n<p>\u00a0Solve eq 1 and eq 4 simultaneously.<br \/>\n3x \u2013 y = 3 &#8212;&#8212;&#8212; eq 1<br \/>\n3x + y = 15 &#8212;&#8212;&#8211; eq 4<br \/>\neq 1 + eq 4<br \/>\n6x  =  18<br \/>\nx  =  18\/ 6<br \/>\nx = 3<br \/>\nSubstitute x = 3 into eq 4.<br \/>\n3x + y = 15<br \/>\n3 (3) + y = 15<br \/>\n9 + y = 15<br \/>\ny = 15 \u2013 9<br \/>\ny = 6<br \/>\n\\ x = 3, y = 6<\/p>\n<p>\u00a0<strong>Evaluation<br \/>\n<\/strong>Solve    for x   and   y in the following pairs of   equations<br \/>\n1. (a) 4x<sup>2<\/sup> \u2013 y<sup>2<\/sup> = 15                              (b) 3x<sup>2<\/sup> +5xy \u2013y<sup>2<\/sup> =3<br \/>\n            2x \u2013 y = 5                                               x  &#8211;  y  = 4<\/p>\n<p>\u00a0<strong>WORD   PROBLEMS LEADING TO LINEAR AND QUADRATIC EQUATIONS<br \/>\n<\/strong><strong>Example<br \/>\n<\/strong>The product of two numbers is 12. The sum of the larger number and twice the smaller number is 11. Find the two numbers.<strong><br \/>\n\t\t\t<\/strong><strong>Solution<br \/>\n<\/strong> Let    x  = the larger number<br \/>\ny  = the smaller number<br \/>\nProduct,  x y  =  12    \u2026\u2026\u2026\u2026\u2026.eq1<br \/>\n      From the last statement,<br \/>\n                          x + 2y  =  11  \u2026\u2026\u2026\u2026.. eq2<br \/>\n       From eq2,   x  =  11 \u2013 2y   \u2026\u2026\u2026\u2026&#8230;eq3<br \/>\n       Sub. Into  eq1<br \/>\ny(11 \u2013 2y) = 12<br \/>\n                            11y \u2013 2y2  = 12<br \/>\n                             2y2 -11y + 12 = 0<br \/>\n                            2y2 \u2013 8y \u2013 3y + 12 = 0<br \/>\n                             2y(y-4) \u2013 3(y-4) = 0<br \/>\n                              (2y-3)(y-4)  =0<br \/>\n                               2y-3 =0 or  y-4 =0<br \/>\n                                 2y = 3 or   y = 4<br \/>\n                                   y= 3\/2 or 4<br \/>\nwhen y = 3\/2                                             when  y=4<br \/>\n        x = 11 \u2013 2y                                      x = 11- 2y<br \/>\n        x = 11 \u2013 2(3\/2)                                  x = 11 \u2013 2(4)<br \/>\n        x = 11 \u2013 3                                           x = 11 \u2013 8<br \/>\n         x = 8                                                  x = 3<br \/>\nTherefore, (8 , 3\/2)(3 , 4)<strong><br \/>\n\t\t\t\t<\/strong><br \/>\n\u00a0<strong>Evaluation<br \/>\n<\/strong>Solve the following simultaneous equation\u00a0\u00a0\u00a0\u00a0<br \/>\n1. (a)  2<sup>2x-3y <\/sup>= 32,   3<sup>x-2y <\/sup>= 81      (b) 2<sup>x+2y<\/sup>=1, 3<sup>2x+y <\/sup>= 27<br \/>\n2. Bisi&#8217;s and Fibie&#8217;s ages add up to 29. Seven  years  ago  Bisi  was  twice  as  old  as  Fibie. Find their present ages.<\/p>\n<p>\u00a0<strong>SOLVING SIMULTANEOUS EQUATIONS USING GRAPHICAL METHOD<br \/>\n<\/strong><strong>Examples<br \/>\n<\/strong>Using the scale 2cm to 1 units on x-axis and 2cm to 2 unit on y-axis, draw the graph of y = x<sup>2<\/sup> \u2013 x \u2013 1 and y = 2x \u2013 1 (on the same scale and axis for values of x: &#8211; 3\u2264x&lt; 4<\/p>\n<p>\u00a0<strong>Solution<br \/>\n<\/strong><strong>Table of values for y = x<sup>2<\/sup> \u2013 x \u2013 1<br \/>\n<\/strong><\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td><strong>X<\/strong><\/td>\n<td><strong>-3<\/strong><\/td>\n<td><strong>-2<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>0<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<td><strong>3<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>x<sup>2<\/sup><\/strong><\/td>\n<td><strong>9<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>0<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<td><strong>9<\/strong><\/td>\n<td><strong>16<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>-x<\/strong><\/td>\n<td><strong>+3<\/strong><\/td>\n<td><strong>+2<\/strong><\/td>\n<td><strong>+1<\/strong><\/td>\n<td><strong>0<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-2<\/strong><\/td>\n<td><strong>-3<\/strong><\/td>\n<td><strong>-4<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Y<\/strong><\/td>\n<td><strong>11<\/strong><\/td>\n<td><strong>5<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>5<\/strong><\/td>\n<td><strong>11<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>\u00a0<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>X<\/td>\n<td>-3<\/td>\n<td>-2<\/td>\n<td>&#8211; 1<\/td>\n<td>0<\/td>\n<td>1<\/td>\n<td>2<\/td>\n<td>3<\/td>\n<td>4<\/td>\n<\/tr>\n<tr>\n<td>Y<\/td>\n<td>11<\/td>\n<td>5<\/td>\n<td>1<\/td>\n<td>-1<\/td>\n<td>-1<\/td>\n<td>1<\/td>\n<td>5<\/td>\n<td>11<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>\u00a0<strong>Table of values for y = 2x \u2013 1<br \/>\n<\/strong><\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td><strong>X<\/strong><\/td>\n<td><strong>-3<\/strong><\/td>\n<td><strong>-2<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>0<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>2x<\/strong><\/td>\n<td><strong>-6<\/strong><\/td>\n<td><strong>-4<\/strong><\/td>\n<td><strong>-2<\/strong><\/td>\n<td><strong>0<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Y<\/strong><\/td>\n<td><strong>-7<\/strong><\/td>\n<td><strong>-5<\/strong><\/td>\n<td><strong>-3<\/strong><\/td>\n<td><strong>-1<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>3<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>\u00a0<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>X<\/td>\n<td>-3<\/td>\n<td>&#8211; 2<\/td>\n<td>&#8211; 1<\/td>\n<td>0<\/td>\n<td>1<\/td>\n<td>2<\/td>\n<td>3<\/td>\n<\/tr>\n<tr>\n<td>Y<\/td>\n<td>-7<\/td>\n<td>-5<\/td>\n<td>&#8211; 3<\/td>\n<td>&#8211; 1<\/td>\n<td>1<\/td>\n<td>3<\/td>\n<td>5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p><img decoding=\"async\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1601_Week8SS2Fi3.png\" alt=\"\"\/><strong><br \/>\n\t\t\t<\/strong><br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<strong>Evaluation<br \/>\n<\/strong>a. Copy and complete the table below of values  for  the relation  y = 2x<sup>2<\/sup> \u2013 3x \u2013 7<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td> x<\/td>\n<td>-2<\/td>\n<td>-1<\/td>\n<td>0<\/td>\n<td>1<\/td>\n<td>2<\/td>\n<td>3<\/td>\n<td>4<\/td>\n<td>5<\/td>\n<\/tr>\n<tr>\n<td>y<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<td>\u00a0<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>b.Using a scale of 2cm to 1 unit on x-axis and 2cm to 5 unit on y-axis, draw the graph of the relation<br \/>\n            y = 2x<sup>2<\/sup>-3x-7 for -3 &lt;  x \u2264 5<br \/>\nc.Using the same scale and axis, draw the graph of y = 2x-1<br \/>\nd. Use  your graph to find the values of x and y.<\/p>\n<p>\u00a0<strong>GENERAL EVALUATION AND REVISION QUESTIONS<\/strong><br \/>\n\t\t1. Solve  the   simultaneous  equation:   3x<sup>2<\/sup>  &#8211;  4y  = -1  &amp; 2x  &#8211;  y  = 1<br \/>\n2. Five  years  ago, a  father  was  3  times  as  old  as  his  son, now  their  combined  ages  amount  to  110  years. How old are they?<br \/>\n3. Solve:  4x<sup>2<\/sup> &#8211; y<sup>2<\/sup> = 15   &amp;  2x  &#8211;  y =  5<br \/>\n4. Seven cups and eight plates cost # 1750.  Eight cups and seven plates cost #1700. Calculate the cost of a cup and  of  a  plate.<\/p>\n<p>\u00a0<strong>WEEKEND ASSIGNMENT        <\/strong><br \/>\n\t\tSolve each of the following pairs of equations simultaneously,<br \/>\n1.  xy = -12 ; x \u2013 y = 7   a. (3 , -4)(4 ,-3) \u00a0\u00a0\u00a0\u00a0  b. (-2 ,4)(-3, -4)    c.(-4, 5)(-2 , 3)     d.(3 ,-3)(4,-4)<br \/>\n2.  x \u2013 5y = 5 ; x<sup>2<\/sup> \u2013 25y<sup>2<\/sup> = 55   a (-8, 0)(3\/5 , 0)     b. (0, 0)(-8 , 3\/5)    c. (8 , 3\/5) d. (0, 8)(0, 3\/5)<br \/>\n3.  y = x<sup>2<\/sup> and y = x + 6     (a).(0,6) (3,9)      (b)(-3,0) (2,4)      (c)  (-2,4) (3,9)     (d).(-2, 3), (-3,2)<br \/>\n4.  x \u2013 y = -3\/2 ;  4x<sup>2<\/sup> + 2xy \u2013 y<sup>2<\/sup> = 11\/4 : a. (-1, 1\/2)(1, 5\/2).           b. (3, 2\/5) (1, 1\/2)         c.(3\/2 , -1) (4,2)              d.(-1 , -1\/2)(-1 , 5\/2)<br \/>\n5.  m<sup>2<\/sup> + n<sup>2<\/sup> = 25 ; 2m + n \u2013 5 = 0 : a. (0,5)(4, -3) b.(5,0)(-3,4)c.(4,0)(-3,5) d(-5,3)(0,4)<\/p>\n<p>\u00a0<strong>THEORY<br \/>\n<\/strong>1a. Find the coordinate of the points where the line 2x \u2013 y = 5 meets the curve 3x<sup>2<\/sup> \u2013 xy -4 =10<br \/>\nb. Solve the simultaneous equation: 2<sup>2x+4y <\/sup>= 4, 3<sup>3x + 5y <\/sup>\u2013 81= 0<br \/>\n2.  A woman is q years old while her son is p years old. The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675.<br \/>\nWrite down the equations connecting their ages and solve the equations in order to find the ages of the woman and her son. (WAEC)<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<strong><br \/>\n\t\t\t<\/strong>\u00a0<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u00a0WEEK EIGHT TOPIC: SIMULTANEOUS EQUATIONS CONTENT Solving Simultaneous Equations Involving One linear and One quadratic&#8230;.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,233],"tags":[],"class_list":["post-2897","post","type-post","status-publish","format-standard","hentry","category-posts","category-first-term-ss2-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2897","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=2897"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2897\/revisions"}],"predecessor-version":[{"id":2898,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2897\/revisions\/2898"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=2897"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=2897"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=2897"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}