{"id":2889,"date":"2023-10-03T15:58:59","date_gmt":"2023-10-03T15:58:59","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=2889"},"modified":"2023-10-03T16:03:34","modified_gmt":"2023-10-03T16:03:34","slug":"week-3-ss2-first-term-mathematics-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-3-ss2-first-term-mathematics-notes\/","title":{"rendered":"Week 3 &#8211; SS2 First Term Mathematics Notes"},"content":{"rendered":"<p>\u00a0<br \/>\n\u00a0<strong>WEEK THREE<br \/>\n<\/strong><strong>TOPIC: ARITHMETIC PROGRESSION (A. P)<br \/>\n<\/strong><strong>CONTENT<br \/>\n<\/strong><\/p>\n<ul>\n<li>Sequence\n<\/li>\n<li>Definition of Arithmetic Progression\n<\/li>\n<li>Denotations in Arithmetic progression\n<\/li>\n<li>Deriving formulae for the term of A. P.\n<\/li>\n<li>Sum of an arithmetic series\n<\/li>\n<\/ul>\n<p>Find the next two terms in each of the following sets of number and in each case state the rule which gives the term.<br \/>\n(a)\u00a0\u00a0\u00a0\u00a01, 5, 9, 13, 17, 21, 25(any term +4 = next term)<br \/>\n(b)\u00a0\u00a0\u00a0\u00a02, 6, 18, 54, 162, 486, 1458 (any term x 3 = next term)<br \/>\n(c)\u00a0\u00a0\u00a0\u00a01, 9, 25, 49, 81, 121, 169<strong>,<\/strong> (sequence of consecutive odd no)<br \/>\n(d)\u00a0\u00a0\u00a0\u00a010, 9, 7, 4, 0, -5, -11, <strong>&#8211;<\/strong>18, -26<strong>,<\/strong> (starting from 10, subtract 1, 2, 3 from immediate no).<\/p>\n<p>\u00a0In each of the examples below, there is a rule which will give more terms in the list. A list like this is called a SEQUENCE in many cases; it can simply matter if a general term can be found for a sequence e.g.<br \/>\n1, 5, 9, 13, 17 can be expressed as<br \/>\n1, 5, 9, 13, 17 \u2026\u2026\u2026\u2026\u2026. 4n \u2013 3 where n = no of terms<br \/>\nCheck: 5<sup>th<\/sup> term    = 4(5) -3<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0  20 \u2013 3 = <strong>17<\/strong><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a010<sup>th<\/sup> term = 4(10) \u2013 3<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0     40 \u2013 3 = <strong>37<\/strong><br \/>\n\t\t<strong>Example 2<br \/>\n<\/strong>Find the 6<sup>th<\/sup> and 9<sup>th<\/sup> terms of the sequence whose nth term is<br \/>\n(a)\u00a0\u00a0\u00a0\u00a0(2n + 1)<br \/>\n(b)\u00a0\u00a0\u00a0\u00a03 \u2013 5n.<br \/>\n<strong>Solution<br \/>\n<\/strong>(a)\u00a0\u00a0\u00a0\u00a02n + 1<br \/>\n<strong>\u00a0\u00a0\u00a0\u00a0<\/strong>6<sup>th<\/sup> term\u00a0\u00a0\u00a0\u00a0=   2(6) + 1   = 12 + 1 = 13<br \/>\n\u00a0\u00a0\u00a0\u00a09<sup>th<\/sup> term\u00a0\u00a0\u00a0\u00a0=   2 (9) + 1  = 18 + 1 = 19<br \/>\n(b)\u00a0\u00a0\u00a0\u00a03 \u2013 5n<br \/>\n\u00a0\u00a0\u00a0\u00a06<sup>th<\/sup> term\u00a0\u00a0\u00a0\u00a0= 3 \u2013 5 (6) = 3 \u2013 30 = <strong>-27<\/strong><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a09<sup>th<\/sup> term\u00a0\u00a0\u00a0\u00a0= 3 \u2013 5 (9) = 3 \u2013 45 = &#8211;<strong>42<\/strong><br \/>\n\t\t<strong>Evaluation<br \/>\n<\/strong>For each of the following sequence, find the next two terms and the rules which give the term.<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1558_Week3SS2Fi1.png\" alt=\"\"\/><img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1558_Week3SS2Fi2.png\" alt=\"\"\/><img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1558_Week3SS2Fi3.png\" alt=\"\"\/><img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1558_Week3SS2Fi4.png\" alt=\"\"\/><strong><br \/>\n\t\t\t\t<\/strong>1.\u00a0\u00a0\u00a0\u00a01,   , ,      ,       , ____,  ____<\/p>\n<p>\u00a02\u00a0\u00a0\u00a0\u00a0100, 96, 92, 88, _____, ____<br \/>\n3.\u00a0\u00a0\u00a0\u00a02, 4, 6, 8, 10,   ____, _____<br \/>\n4.\u00a0\u00a0\u00a0\u00a01, 4, 9, 16, 25,   ____, _____<br \/>\n(i) Arrange the numbers in ascending order   (ii) Find the next two terms in the sequence<br \/>\n5.\u00a0\u00a0\u00a0\u00a019, 13, 16, 22, 10<br \/>\n6.\u00a0\u00a0\u00a0\u00a0-2<sup>1<\/sup>\/<sub>2<\/sub>, 5<sup>1<\/sup>\/<sub>2<\/sub>, 3<sup>1<\/sup>\/<sub>2<\/sub>, 1<sup>1<\/sup>\/<sub>2<\/sub>, &#8211;<sup>1<\/sup>\/<sub>2<\/sub><br \/>\n\t\t7.\u00a0\u00a0\u00a0\u00a0Find the 15<sup>th<\/sup> term of the sequence whose nth term is 3n &#8211; 5<br \/>\n\t\t                                                                                                    4\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<br \/>\n<strong>DEFINITION OF ARITHMETIC PROGRESSION<br \/>\n<\/strong>A sequence in which the terms either increase or decrease in equal steps is called an Arithmetic Progression.<strong><br \/>\n\t\t\t<\/strong>The sequence 9, 12, 15, 18, 21, ____,  _____,  _____ has a first term of 9 and a common difference of +3 between the terms.<br \/>\n<strong>Denotations in A. P.<br \/>\n<\/strong>a\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a01<sup>st<\/sup> term<br \/>\nd\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0common difference<br \/>\nn\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0no of terms<br \/>\nU<sub>n<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0nth term<br \/>\nS<sub>n<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0Sum of the first n terms<\/p>\n<p>\u00a0<strong>Formula for nth term of Arithmetic Progression<br \/>\n<\/strong>e.g. in the sequence 9, 12, 15, 18, 21.<br \/>\na\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a09<br \/>\nd\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a012 \u2013 9   or   18 \u2013 15 = 3.<br \/>\n1<sup>st<\/sup> term\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0U<sub>1<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=    a<br \/>\n2<sup>nd<\/sup> term\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0U<sub>2<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a09 + 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=    a + d<br \/>\n3<sup>rd<\/sup> term\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0U<sub>3<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a09 + 3 + 3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=    a + 2d<br \/>\n10<sup>th<\/sup> term \u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0U<sub>10<\/sub> = 9 + 9(3)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0            =    a + 9d<br \/>\nnth term \u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0U<sub>n<\/sub> = 9+(n-1)3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=   a + (n-1)d<br \/>\n\\<strong>nth term<\/strong>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0<strong>U<sub>n<\/sub>  = a + (n-1)d<br \/>\n<\/strong><br \/>\n\u00a0<strong>Example:<br \/>\n<\/strong>1.Given the A.P, 9, 12, 15, 18 \u2026\u2026 find the 50<sup>th<\/sup> term.<br \/>\na   =  9        d    =  3      n    =  50         U<sub>n<\/sub>  =  U<sub>50<\/sub><br \/>\n\t\tU<sub>n<\/sub>=  a + (n-1) d<br \/>\nU<sub>50<\/sub>  =  9 + (50-1) 3<br \/>\n        = 9 + (49) 3<br \/>\n        = 9 + 147<br \/>\n        = <strong>156<br \/>\n<\/strong>2.The 43<sup>rd<\/sup> term of an AP is 26, find the 1<sup>st<\/sup> term of the progression given that its common difference is \u00bd and also find the 50<sup>th<\/sup> term.<br \/>\nU<sub>43<\/sub>=  26       d\u00a0\u00a0\u00a0\u00a0=  \u00bd                a\u00a0\u00a0\u00a0\u00a0=  ?          n   = 43<br \/>\nU<sub>n<\/sub> = a + (n-1) d<br \/>\n26 = a + (43-1) \u00bd<br \/>\n26 = a + 42(<sup>1<\/sup>\/<sub>2<\/sub>)<br \/>\n26 = a + 21<br \/>\n26 \u2013 21 = a<br \/>\n5 = a<br \/>\na = <strong>5<br \/>\n\t\t\t\t<\/strong>(b)\u00a0\u00a0\u00a0\u00a0a      =  5              d      = \u00bd           n = 50     U<sub>50<\/sub>   =?<br \/>\n\u00a0\u00a0\u00a0\u00a0U<sub>n<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a0a + (n-1) d<br \/>\n\u00a0\u00a0\u00a0\u00a0U<sub>50<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a05 + (50-1)<sup>1<\/sup>\/<sub>2<\/sub><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a05 + 49(<sup>1<\/sup>\/<sub>2<\/sub>)<br \/>\n\u00a0\u00a0\u00a0\u00a0U<sub>50<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a05 + 24<sup>1<\/sup>\/<sub>2<\/sub><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a0U<sub>50<\/sub>\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a029<sup>1<\/sup>\/<sub>2<\/sub><br \/>\n\t\t<strong>Evaluation<br \/>\n<\/strong>1.\u00a0\u00a0\u00a0\u00a0Find the 37<sup>th<\/sup> term of the sequence 20, 10, 0, -10\u2026<br \/>\n2.\u00a0\u00a0\u00a0\u00a01, 5\u2026 69 are the 1<sup>st<\/sup>, 2<sup>nd<\/sup>, and last term of the sequence; find the common difference between them and the number of terms in the sequence.<\/p>\n<p>\u00a0<strong>SUM OF AN ARITHMETIC SERIES<br \/>\n<\/strong>When the terms of a sequence are added, the resulting expression is called series e.g. in the sequence 1, 3, 5, 7, 9, 11.<br \/>\nSeries\u00a0\u00a0\u00a0\u00a0=\u00a0\u00a0\u00a0\u00a01 + 3 + 5 + 7 + 9 + 11<\/p>\n<p>\u00a0When the terms of a sequence are unending, the series is called infinite series, it is often impossible to find the sum of the terms in an infinite series.<br \/>\ne.g.  1 + 3 + 5 + 7 + 9 + 11 + \u2026\u2026\u2026\u2026\u2026\u2026\u2026. Infinite<\/p>\n<p>\u00a0Sequence with last term or nth term is termed finite series.<strong><br \/>\n\t\t\t\t<\/strong>e.g.<\/p>\n<p>\u00a0Find the sum of<br \/>\n1, 3, 5, 7, 9, 11, 13, 15<\/p>\n<p>\u00a0If sum = 2, n = 8<br \/>\nThen<br \/>\nS = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15<br \/>\nOr \u00a0\u00a0\u00a0\u00a0S = 15 + 13 + 11 + 9 + 7 + 5 + 3 + 1<br \/>\n\u00a0\u00a0\u00a0\u00a0Add eqn1 and eqn 2<\/p>\n<p>\u00a02s = 16 + 16 + 16 + 16 + 16 + 16 + 16 + 16<br \/>\n\u00a0\u00a0\u00a0\u00a0=  48   =    8(16)<br \/>\n\t\t                  2              2        =    S   = <strong>64<br \/>\n\t\t\t\t<\/strong>Deriving the formula for sum of A. P. The following represent a general arithmetic series when the terms are added.<br \/>\nS = a + (a+d) + a + 2d + \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 + (L-2d) + (L-d) + L \u2013 eqn<br \/>\nS = L + (L-d) + L \u2013 2d + \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 a + 2d + (a+d) + a \u2013 eqn<br \/>\n2s = (a + L) + (a + L) + (a + L) + \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026 (a + L) + (a + L) + (a + L)<br \/>\n2s = n(a + L)<br \/>\n\t\t             2<br \/>\nS = n(a+L)<br \/>\n\t\t          2<br \/>\nL   =&gt;  Un  =  a + (n-1)d<br \/>\nSubstitute L into eq**<br \/>\nS = n(a + a+(n-1)d<br \/>\n                 2   <strong><br \/>\n\t\t\t<\/strong><strong>S = n(2a + (n-1)d    = n ( 2a+ (n-1)d<br \/>\n<\/strong>\u00a0\u00a0\u00a0\u00a0<strong>22<\/strong><br \/>\n\t\t<strong>\\<\/strong><strong>  S = n<\/strong>[a + L]    where   L  is the last  term i.e    U<sub>n<\/sub><br \/>\n\t\t\t<strong>2<br \/>\n<\/strong>or<br \/>\n<strong>S  =n<\/strong>[2a +(n-1)d]  when d is given or obtained<br \/>\n<strong>2<br \/>\n<\/strong><strong>Example 2<br \/>\n<\/strong>Find the sum of the 20<sup>th<\/sup> term of the series 16 + 9 + 2 + \u2026\u2026\u2026\u2026\u2026\u2026\u2026<\/p>\n<p>\u00a0a = 16           d = 9 \u2013 16 = -7           n = 20<br \/>\nS = n(2a + (n-1)d)<br \/>\n\t\t               2<br \/>\nS = 20 (2&#215;16) + (20-1)(-7)<br \/>\n\t\t\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02<br \/>\n=     20 (32 + 19(-7)<br \/>\n                2<\/p>\n<p>\u00a0S =10 (32 &#8211; 133) = 10(-101)<br \/>\n\u00a0\u00a0\u00a0\u00a0<br \/>\nS = -1010<\/p>\n<p>\u00a0<strong>EVALUATION<br \/>\n<\/strong>1. Find the sum of the arithmetic series with 16 and -117 as the first and 20<sup>th<\/sup> term respectively.<strong><br \/>\n\t\t\t\t<\/strong>2. The salary scale for a clerical officer starts at N55, 200 per annum. A rise of N3, 600 is given at the end of each year; find the total amount of money earned in 12 years.<\/p>\n<p>\u00a0<strong>GENERAL EVALUATION \/REVISION QUESTION<br \/>\n<\/strong>1. An A. P. has 15 terms and a common difference of -3, find its first and last term if its sum is 120.<br \/>\n2. On the 1<sup>st<\/sup> of January, a student puts N10 in a box, on the 2<sup>nd<\/sup> she puts N20 in the box, on the 3<sup>rd<\/sup> she puts N30 and so on putting on the same no. of N10 notes as the day of the month. How much will be in the box if she keeps doing this till 16<sup>th<\/sup> January?<br \/>\n3. The salary scale for a clerical officer starts at N55, 200 per annum. A rise of N3, 600 is given at the end of each year, find the total amount of money earned in 12 years.<br \/>\n4<strong>. <\/strong>Find  the  7<sup>th<\/sup>  term  and  the  nth  term  of  the  progression  27,9,3,\u2026<br \/>\n5. If 8, x, y, &#8211; 4 are in A.P, find x and y.<\/p>\n<p>\u00a0<strong>WEEKEND ASSIGNMENT<br \/>\n<\/strong>1.\u00a0\u00a0\u00a0\u00a0Find the 4<sup>th<\/sup> term of an A. P. whose first term is 2 and the common difference is 0.5   (a) 4   (b) 4.5    (c) 3.5     (d) 2.5<br \/>\n2.\u00a0\u00a0\u00a0\u00a0In an A. P. the difference between the 8<sup>th<\/sup> and 4<sup>th<\/sup> term is 20 and the 8<sup>th<\/sup> term is 1<sup>1<\/sup>\/<sub>2<\/sub> times the 4<sup>th<\/sup> term, find the common difference         (a) 5    (b) 7     (c) 3    (d) 10<br \/>\n3.\u00a0\u00a0\u00a0\u00a0Find the first term of the sequence in no. 2        (a) 70     (b) 45    (c) 25     (d) 5<br \/>\n4.\u00a0\u00a0\u00a0\u00a0The next term of the sequence 18, 12, 60 is       (a) 12     (b) 6    (c) -6    (d) -12<br \/>\n5.\u00a0\u00a0\u00a0\u00a0Find the no. of terms of the sequence <sup>1<\/sup>\/<sub>2<\/sub> , \u00be, 1, \u2026\u2026\u2026\u2026\u2026\u2026.. 51\/2     (a) 21    (b) 4<sup>3<\/sup>\/<sub>4<\/sub>      (c) 1     (d) 22<\/p>\n<p>\u00a0<strong>THEORY<\/strong><br \/>\n\t\t1.\u00a0\u00a0\u00a0\u00a0Eight wooden poles are to be used for pillars and the length of the poles form an arc Arithmetic Progression (A. P.) if the second pole is 2m and the 6<sup>th<\/sup> pole is 5m, give the lengths of the poles in order and sum up the lengths of the poles.<br \/>\n2\u00a0\u00a0\u00a0\u00a0a.\u00a0\u00a0\u00a0\u00a0Write down the 15<sup>th<\/sup> term of the sequence.<br \/>\n\u00a0\u00a0\u00a0\u00a0  2_,  3   ,4  ,   5<br \/>\n\u00a0\u00a0\u00a0\u00a01&#215;3   2&#215;4    3&#215;5   4 x6<br \/>\nb.\u00a0\u00a0\u00a0\u00a0An arithmetic progression (A. P.) has 3 as its term and 4 as the common difference.<br \/>\nc.\u00a0\u00a0\u00a0\u00a0Write an expression in its simplest form for the nth term.<br \/>\nd.\u00a0\u00a0\u00a0\u00a0Find   the 10<sup>th<\/sup>  term    and  the  sum   of  the  first  <\/p>\n<p>\u00a0<strong>Reading Assignment<br \/>\n<\/strong>New General Mathematics SSS2 <\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<strong><br \/>\n\t\t\t<\/strong>\u00a0<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u00a0 \u00a0WEEK THREE TOPIC: ARITHMETIC PROGRESSION (A. P) CONTENT Sequence Definition of Arithmetic Progression Denotations&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,233],"tags":[],"class_list":["post-2889","post","type-post","status-publish","format-standard","hentry","category-posts","category-first-term-ss2-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2889","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=2889"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2889\/revisions"}],"predecessor-version":[{"id":2890,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2889\/revisions\/2890"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=2889"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=2889"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=2889"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}