{"id":2599,"date":"2023-10-03T10:31:54","date_gmt":"2023-10-03T10:31:54","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=2599"},"modified":"2023-10-03T10:47:41","modified_gmt":"2023-10-03T10:47:41","slug":"week-3-ss1-third-term-further-mathematics-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-3-ss1-third-term-further-mathematics-notes\/","title":{"rendered":"Week 3 &#8211; SS1 Third Term Further Mathematics Notes"},"content":{"rendered":"<p><strong>WEEK 3<br \/>\n<\/strong><strong><em>Topic:<\/em><\/strong> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Gradients of straight lines and curves<br \/>\n<strong><em>Sub-topic:<\/em><br \/>\n\t\t\t\t<\/strong>\u00a0\u00a0\u00a0\u00a0Gradients of straight lines<br \/>\n<strong><em>Duration:<\/em><\/strong> 40 minutes<br \/>\n<strong><em>Learning Objectives:<\/em><\/strong> By the end of the lesson, students should be able to calculate the gradient of a straight line.<br \/>\n<strong><em>Reference Materials:<\/em><\/strong> i. New General Mathematics for SSS 2, by M.F Macrae et al. Pages 184 \u2013 192.<br \/>\n<strong><em>Previous Knowledge<\/em>:<\/strong> Students can draw the graph of a linear equation (straight-line graph).<br \/>\n<strong><em>Instructional Materials<\/em>:<\/strong> Graph board and graph book.<br \/>\n<strong><em>Content:\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/em>GRADIENT OF A STRAIGHT LINE<em><br \/>\n\t\t\t\t\t<\/em><\/strong>The gradient of a straight line is the rate of change of y compared with x.<br \/>\nFor example, if the gradient is 2, then for any increase in x, y increases two times as much.<br \/>\n<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th1.png\" alt=\"\"\/><\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0Gradient of AB =\u00a0\u00a0\u00a0\u00a0Increase in y from A to B  =  MB\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Increase in x from A to B\u00a0\u00a0\u00a0\u00a0AM<\/p>\n<p>\u00a0<strong>Example<br \/>\n<\/strong>Find the gradient of the line joining P(7, -2) and Q(-1, 2)<br \/>\n<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th2.png\" alt=\"\"\/><img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th3.png\" alt=\"\"\/>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0Gradient of PQ = increase in y   =    &#8211;    AQ<\/p>\n<p>\t\t\t\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0       Increase in x                PA<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 = <strong><br \/>\n\t\t\t\t<\/strong><br \/>\n\u00a0<strong>Example 2<br \/>\n<\/strong>Find the gradient of the line 7x + 4y \u2013 8 = 0<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Re-arrange the equation: 4y = &#8211; 7x + 8<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0           y =  + 2<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Therefore, gradient (m) =  , y \u2013 intercept (c) = 2<br \/>\n<strong>SKETCHING GRAPHS OF STRAIGHT LINES<em><br \/>\n\t\t\t\t\t<\/em><\/strong>\u00a0\u00a0\u00a0\u00a0Given the equation<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0y = 3x \u2013 2 , gradient = 3, y \u2013 intercept(c) = -2<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02x + 3y = 6, gradient =  , y \u2013 intercept(c) = 2<\/p>\n<p>\u00a0<strong>Example<br \/>\n<\/strong>Sketch the graph of the line whose equation is 4x \u2013 3y = 12<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<strong>Solution<\/strong><br \/>\n\t\tWhen x = 0 ,- 3y = 12<br \/>\n  y = &#8211; 4<br \/>\nThe line crosses the y \u2013 axis at (0, &#8211; 4).<br \/>\nWhen y = 0 , 4x = 12<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x = 3<br \/>\nThe line crosses the x \u2013 axis at (3, 0).<br \/>\n<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th4.png\" alt=\"\"\/>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0From the graph:<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Gradient m =  <\/p>\n<p>\u00a0                                                                                                                       =    =<br \/>\n                                                                                              y \u2013 intercept = &#8211; 4<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<strong>Lines parallel to axes<br \/>\n<\/strong>Any line parallel to the x \u2013 axis has a gradient of zero. The equation of such lines is always in the form<br \/>\n<strong><em>y = c<\/em><\/strong>, where <strong><em>c<\/em><\/strong> may be any number.<br \/>\nThe figure below shows the graph of y = 5 and y = &#8211; 3.<br \/>\nNotice that the equation of the x \u2013 axis is y = 0<br \/>\n<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th5.png\" alt=\"\"\/><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;-<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0The gradient of a line that is parallel to the y \u2013 axis is undefined. The equations of such a lines are always in the form <strong>x = <em>a<\/em><\/strong> , where <strong><em>a<\/em><\/strong> may be any number.<br \/>\nThe figure below shows the graph of line x = 2 and x = &#8211; 4.<br \/>\nNotice that the equation of the y \u2013 axis is x = 0<\/p>\n<p>\u00a0<img decoding=\"async\" align=\"left\" src=\"https:\/\/ecolebooks.com\/nigeria\/wp-content\/uploads\/9jalessonsimages\/100323_1031_Week3SS1Th6.png\" alt=\"\"\/><br \/>\n\t\t\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<br \/>\n\u00a0<strong>EQUATION OF A STRAIGHT LINE<em><br \/>\n\t\t\t\t\t<\/em><\/strong>Equation of a straight line is of the form y = mx + c, where m is the gradient and c is the y \u2013 intercept.<\/p>\n<p>\u00a0<strong>Example 1<br \/>\n<\/strong>Determine the equation of a straight line whose gradient is  and passes through the point (- 3, 2).<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<strong>Solution<\/strong><br \/>\n\t\tUsing the formula y \u2013 y<sub>1<\/sub> = m(x &#8211; x<sub>1<\/sub>)<br \/>\nWhere (x<sub>1<\/sub>, y<sub>1<\/sub>) = (- 3, 2) and m =<br \/>\n\u00a0\u00a0\u00a0\u00a0y \u2013 2 =  (x + 3)<br \/>\n\u00a0\u00a0\u00a0\u00a03y \u2013 6 = &#8211; x \u2013 3<br \/>\n\u00a0\u00a0\u00a0\u00a0x + 3y = 3<\/p>\n<p>\u00a0<strong>Example 2<br \/>\n<\/strong>Find the equation of the straight line passing through the points (1, 4) and (- 2, 6).<br \/>\nUsing the formula<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0    =<br \/>\nWhere = (x<sub>1<\/sub>, y<sub>1<\/sub>) = ( 1, 4) and (x<sub>2<\/sub>, y<sub>2<\/sub>) = (- 2, 6), the equation is<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0cross multiply<br \/>\n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0&#8211; 3y + 12 = 2x \u2013 2<br \/>\n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0   2x + 3y = 14<br \/>\n<strong>GRADIENT OF A CURVE<em><br \/>\n\t\t\t\t\t<\/em><\/strong><strong>Example<br \/>\n<\/strong>Draw the graph of y =  for values of x from \u20132 to 3. Find the gradient of the curve at the point where x has the value (a) (b) \u2013 2<br \/>\n<strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Solution<br \/>\n<\/strong><\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td>x<\/td>\n<td>-2<\/td>\n<td>-1<\/td>\n<td>0<\/td>\n<td>1<\/td>\n<td>2<\/td>\n<td>3<\/td>\n<\/tr>\n<tr>\n<td>y<\/td>\n<td>1<\/td>\n<td>\u00bc<\/td>\n<td>0<\/td>\n<td>\u00bc<\/td>\n<td>1<\/td>\n<td>2\u00bc<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>\u00a0(a) Gradient of the curve where x = 3<br \/>\n\u00a0\u00a0\u00a0\u00a0= gradient of tangent PT<br \/>\n\u00a0\u00a0\u00a0\u00a0=  \u00a0\u00a0\u00a0\u00a0= 2.25\u00a0\u00a0\u00a0\u00a0     = 2\u00bc       =  9      =  1<sup>1<\/sup>\/<sub>2<\/sub>\u00a0\u00a0\u00a0\u00a0<br \/>\n\u00a0\u00a0\u00a0\u00a0                       1.5\u00a0\u00a0\u00a0\u00a0         1.5             6<br \/>\n(b) Gradient of curve where x = &#8211; 2<br \/>\n\u00a0\u00a0\u00a0\u00a0= gradient of tangent QR<br \/>\n             = &#8211;       = &#8211;  1\u00a0\u00a0\u00a0\u00a0= &#8211; 1     \u00a0\u00a0\u00a0\u00a0<br \/>\n\u00a0\u00a0\u00a0\u00a0                    1<\/p>\n","protected":false},"excerpt":{"rendered":"<p>WEEK 3 Topic: \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Gradients of straight lines and curves Sub-topic: \u00a0\u00a0\u00a0\u00a0Gradients of straight lines Duration:&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,216],"tags":[],"class_list":["post-2599","post","type-post","status-publish","format-standard","hentry","category-posts","category-third-term-ss1-further-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2599","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=2599"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2599\/revisions"}],"predecessor-version":[{"id":2600,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/2599\/revisions\/2600"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=2599"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=2599"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=2599"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}