{"id":184,"date":"2023-09-25T07:05:31","date_gmt":"2023-09-25T07:05:31","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=184"},"modified":"2023-09-25T07:21:23","modified_gmt":"2023-09-25T07:21:23","slug":"week-9-jss-1-first-term-general-mathematics-lesson-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-9-jss-1-first-term-general-mathematics-lesson-notes\/","title":{"rendered":"Week 9 – Jss 1 First Term General Mathematics Lesson Notes"},"content":{"rendered":"

\u00a0WEEK 9\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0L.C.M AND H.C.F (LOWEST AND HIGHEST COMMON FACTOR)
\n<\/em><\/strong>COMMON MULTIPLES AND FACTOR
\n<\/strong>
\n\u00a0A prime number is a number that can only divide itself. it has two factor which is 1 and itself. Examples of prime numbers are: 2 ,3, 5, 7, 11, 13, 17, 19 etc.
\nMultiples:<\/strong> A multiple of a number is obtained by multiplying it by any whole number. Example the multiple of 4 are 4, 8, 12, 16, 20 , 24 etc.
\nFactors:<\/strong> The factor of a number is the whole number that divides the number exactly.
\nExample 1: <\/strong>(a) find all the factors of 18
\n\u00a0\u00a0\u00a0\u00a0(b) State which of these factors are even
\n\u00a0\u00a0\u00a0\u00a0( c) state which of these factors are prime numbers
\n\u00a0\u00a0\u00a0\u00a0(d) Write the first three multiple of 18
\nSolution
\n<\/strong><\/p>\n

    \n
  1. Factors of 18 are 1, 2, 3, 6, 9, and 18\n<\/li>\n
  2. The even numbers are 2, 6, and 18\n<\/li>\n
  3. \n
    The prime numbers are 2 and 3\n<\/div>\n

    \u00a0<\/li>\n<\/ol>\n

    Example 2:<\/strong> Find the factor pairs of 56
    \nSolution:
    \n<\/strong>1 \u00d7 56
    \n2 \u00d7 28
    \n4 \u00d7 14
    \n7 \u00d7 8
    \nTherefore the factors of 56 are; <\/strong>1, 2, 4, 7, 8, 14, 28, and 56.
    \nProduct of a Prime Factor
    \n<\/strong>A prime factor is a factor that is also a prime number. You can find the product of prime factors of a number using a prime factor tree method or using the method of dividing repeatedly by the prime numbers.
    \nExample 2:<\/strong> Express the following numbers, 56 and 108, as products of prime factors in index form.
    \nSolution:
    \n<\/strong>\"\"\/Method 1: dividing repeatedly by using prime numbers
    \n\"\"\/\"\"\/\"\"\/2\u00a0\u00a0\u00a0\u00a056\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0108
    \n2\u00a0\u00a0\u00a0\u00a028\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a054\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0
    \n2\u00a0\u00a0\u00a0\u00a014\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a027
    \n7\u00a0\u00a0\u00a0\u00a07\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a09
    \n\u00a0\u00a0\u00a0\u00a01\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0Index form = 23<\/sup> x 7\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a03
    \n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a01\u00a0\u00a0\u00a0\u00a0index form = 22<\/sup> x 32<\/sup>
    \n\t\tMethod 2: Factor tree
    \n\"\"\/\"\"\/\"\"\/\"\"\/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a056\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0108
    \n\"\"\/\"\"\/\"\"\/\"\"\/\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a028\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a054
    \n\"\"\/\"\"\/\"\"\/\"\"\/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a014\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a027
    \n\"\"\/\"\"\/\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a02\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a07\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0
    \n\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a03<\/p>\n

    \u00a0Note that the numbers must be a prime numbers
    \n<\/em><\/strong>EXAMPLE 1:<\/strong> Find the L C M of 18 and 24
    \nSolution:
    \n<\/strong>\"\"\/METHOD 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0METHOD 2\u00a0\u00a0\u00a0\u00a0
    \n<\/strong>\"\"\/\"\"\/\"\"\/2\u00a0\u00a0\u00a0\u00a018\u00a0\u00a0\u00a0\u00a024\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a018 = 2 \u00d73 \u00d73
    \n<\/strong>2\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a012\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a024 = 2 \u00d72 \u00d72 \u00d73
    \n<\/strong>2\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a06\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0L C M = 2 \u00d72 \u00d72 \u00d73 \u00d73
    \n<\/strong>3\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0= 72
    \n<\/strong>3\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a01
    \n<\/strong>\u00a0\u00a0\u00a0\u00a01\u00a0\u00a0\u00a0\u00a01
    \n<\/strong>L C M = 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 = 72\u00a0\u00a0\u00a0\u00a0
    \n<\/strong>Example 2: Find the L C M of 72 and 90
    \nSolution:\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0
    \n<\/strong>METHOD 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0METHOD 2\u00a0\u00a0\u00a0\u00a0<\/strong>\u00a0\u00a0\u00a0\u00a0
    \n\"\"\/\"\"\/\"\"\/2\u00a0\u00a0\u00a0\u00a072\u00a0\u00a0\u00a0\u00a090\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a072 = 2 X 2X 2 X 3 X 3
    \n2\u00a0\u00a0\u00a0\u00a036\u00a0\u00a0\u00a0\u00a045\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a090 = 2X 3 X3 X 5
    \n2\u00a0\u00a0\u00a0\u00a018\u00a0\u00a0\u00a0\u00a045\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0L C M = 2 X 2 X 2 X 3 X 3 X 5
    \n3\u00a0\u00a0\u00a0\u00a09\u00a0\u00a0\u00a0\u00a045\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0= 360
    \n3\u00a0\u00a0\u00a0\u00a03\u00a0\u00a0\u00a0\u00a015
    \n5\u00a0\u00a0\u00a0\u00a01\u00a0\u00a0\u00a0\u00a05
    \n \u00a0\u00a0\u00a0\u00a01\u00a0\u00a0\u00a0\u00a01
    \n2 x 2 x 2 x3 x 3 x 5 = 360
    \nExample 3: Find the H C F of 72 and 96
    \nSolution: find the prime product of the number and pick the common ones
    \n72 = 2 <\/strong>* 2 <\/strong>* 2 <\/strong>* 3 <\/strong>* 3
    \n<\/strong>96 = 2 <\/strong>* 2 <\/strong>* 2 <\/strong>* 2 <\/strong>* 2 <\/strong>* 3
    \n<\/strong>H C F = 2 <\/strong>* 2 <\/strong>* 2 <\/strong>* 3 = 24
    \n<\/strong>DO THESE:
    \n<\/em><\/strong>EXERCISE 4.2; NO 8, 10, 11, 12 AND 18. PAGE 29
    \n<\/em><\/strong>EX 4.5; N0 2 (K L M). PAGE 32
    \n<\/em><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

    \u00a0WEEK 9\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0L.C.M AND H.C.F (LOWEST AND HIGHEST COMMON FACTOR) COMMON MULTIPLES AND FACTOR \u00a0A prime…<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,52],"tags":[],"class_list":["post-184","post","type-post","status-publish","format-standard","hentry","category-posts","category-first-term-jss1-general-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/184","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=184"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/184\/revisions"}],"predecessor-version":[{"id":185,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/184\/revisions\/185"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=184"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=184"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=184"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}