{"id":1119,"date":"2023-09-27T12:16:11","date_gmt":"2023-09-27T12:16:11","guid":{"rendered":"http:\/\/localhost\/ecole9ja\/?p=1119"},"modified":"2023-09-27T12:19:15","modified_gmt":"2023-09-27T12:19:15","slug":"week-4-jss-2-second-term-mathematics-lesson-notes","status":"publish","type":"post","link":"https:\/\/ecolebooks.com\/nigeria\/posts\/week-4-jss-2-second-term-mathematics-lesson-notes\/","title":{"rendered":"Week 4 – Jss 2 Second Term Mathematics Lesson Notes"},"content":{"rendered":"

WEEK 4 SOLVING INEQUALITIES
\nRULES IN SOLVING INEQUALITIES.
\n<\/strong><\/p>\n

    \n
  1. \n
    An inequality remains true when the same quantity is added to<\/strong>, or subtracted from <\/strong>both side.\n<\/div>\n<\/li>\n
  2. \n
    An inequality remains true when both sides are multiplied or divided <\/strong>by the same positive quantity.
    \n<\/strong><\/div>\n<\/li>\n
  3. \n
    An inequality remains true when both sides are multiplied or divided <\/strong>by a negatives quantity provided the inequality sign is reversed.<\/strong>\n\t\t\t\t<\/div>\n<\/li>\n<\/ol>\n

    Example 1:<\/strong> Find the greatest possible value of a X that satisfies the inequality 8 + 2X > 3 + 5X. if X is an integer.
    \nSolution:
    \n8 + 2X > 3 + 5X
    \nSubtract 8 from both sides
    \n2X > 3 \u2013 8 + 5X
    \n2X > -5 + 5X
    \nSubtract 5X from both sides
    \n2X \u2013 5X > -5 = -3x > -5
    \nDivide both sides by -3 and also reverse the inequality
    \nX < 12\/3 [rule three]
    \nThe greatest integer value of X is 1.
    \nExample2:<\/strong> Find the smallest integer value of X that satisfies the inequality 7X \u2013 2 \u2265 5X \u2013 6
    \nSolution:
    \n<\/strong>7X \u2013 2 \u2265 5X \u2013 6
    \nAdd 2 to both sides
    \n7X \u2265 5X \u2013 6 + 2
    \n7X \u2265 5X \u2013 4
    \nSubtract 5X from both sides
    \n7X \u2013 5X \u2265 -4 = 2x \u2265 -4 , Divide both side by 2
    \nX \u2265 -2
    \nWORD PROBLEMS LEADING TO INEQUALITIES
    \nExample 1<\/strong>: David is X years old. In 4 year time his age will still be less than 12 years. (a) Write this information in an inequality in X. (b) Find the maximum age of David to the nearest whole numbers.
    \nSolution:
    \n<\/strong>In 4 year time David age’s will be (X + 4) years.
    \nIf at that time his age will be less than 12, then
    \nX + 4 < 12
    \nSubtract 4 from both sides
    \nX < 12 \u2013 4
    \nX < 8.
    \nThe maximum age of David is 7 years.
    \nExample 2:<\/strong> A man had #X, out of this, he used #1000 to pay his house rent. The amount he had left is not more than 3500. (a) Write this information in an inequality in X (b) Solve for X.
    \nSolution:
    \nThe man used #1000 to pay his house rent out of #X, so the amount left is #(x \u2013 1000).
    \nThis amount is not more than 3500
    \nX \u2013 1000 \u2264 500
    \nAdd 1000 to both sides
    \nX \u2264 500 + 1000 = X \u2264 1500
    \nHence the man had less than or equal to #1500
    \nEVALUATION:<\/strong> PAGE 172 EXERCISE 14.3 N0 3(K,L,M,N AND O), PAGE 173 EX 14.4 N0 1, 2 AND 3
    \nASSIGNMNET:<\/strong> PAGE 172 AND 173 EX 14.3 AND 14.4 N0 5, AND 6, 7, 8 AND 9 IN EX 14.4<\/p>\n","protected":false},"excerpt":{"rendered":"

    WEEK 4 SOLVING INEQUALITIES RULES IN SOLVING INEQUALITIES. An inequality remains true when the same…<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1,111],"tags":[],"class_list":["post-1119","post","type-post","status-publish","format-standard","hentry","category-posts","category-second-term-jss-2-mathematics"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/1119","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/comments?post=1119"}],"version-history":[{"count":1,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/1119\/revisions"}],"predecessor-version":[{"id":1120,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/posts\/1119\/revisions\/1120"}],"wp:attachment":[{"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/media?parent=1119"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/categories?post=1119"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/ecolebooks.com\/nigeria\/wp-json\/wp\/v2\/tags?post=1119"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}