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PYTHAGORAS THEOREM
PYTHAGORAS THEOREM
Pythagoras theorem is used to solve problems involving right angled triangles.
Pythagoras theorem is used to solve problems involving right angled triangles.
Statement:
In a right- angled triangle the square on the hypotenuse is equal to the sum of the squares on the other two sides.
Shown below
Required to prove: c2 = a2 + b2
Construction : Joining L and N. Considering the trapezium PQLN:
Area of the trapezium
but area of trapezium = area Δ PKN + area Δ KQL + area Δ KLN
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Pythagoras theorem
Examples
1.The side s of a triangle containing the right angle have length of 5cm and 12cm.
Find the length of the hypotenuse
Solution
C2= a2 +b2
C2 = 52 + 122
C2 = 25+ 144
C2 = 169
C = ![C:thlbcrtzPYTHAGORAS_THEOREM_F2_filesimage006.gif](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSI0MSIgaGVpZ2h0PSIyNCIgdmlld0JveD0iMCAwIDQxIDI0Ij48cmVjdCB3aWR0aD0iMTAwJSIgaGVpZ2h0PSIxMDAlIiBzdHlsZT0iZmlsbDojY2ZkNGRiO2ZpbGwtb3BhY2l0eTogMC4xOyIvPjwvc3ZnPg==)
C= 13cm
∴ The length of the hypotenuse = 13cm.
2. In figure below if AC =17cm, BC = 8cm, and CD = 12cm find AD
Solution:
![C:thlbcrtz__i__images__i__ee11.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxMDQiIGhlaWdodD0iNjMiIHZpZXdCb3g9IjAgMCAxMDQgNjMiPjxyZWN0IHdpZHRoPSIxMDAlIiBoZWlnaHQ9IjEwMCUiIHN0eWxlPSJmaWxsOiNjZmQ0ZGI7ZmlsbC1vcGFjaXR5OiAwLjE7Ii8+PC9zdmc+)
![C:thlbcrtz__i__images__i__ee21.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxNTEiIGhlaWdodD0iMjM2IiB2aWV3Qm94PSIwIDAgMTUxIDIzNiI+PHJlY3Qgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgc3R5bGU9ImZpbGw6I2NmZDRkYjtmaWxsLW9wYWNpdHk6IDAuMTsiLz48L3N2Zz4=)
![C:thlbcrtz__i__images__i__ee3.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxODEiIGhlaWdodD0iMjU1IiB2aWV3Qm94PSIwIDAgMTgxIDI1NSI+PHJlY3Qgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgc3R5bGU9ImZpbGw6I2NmZDRkYjtmaWxsLW9wYWNpdHk6IDAuMTsiLz48L3N2Zz4=)
EXERCISE
1. Calculate the unknown side of the following triangle
SOLUTION:
172 = 152 + b2
172 = 152 + b2
b2 = 172 – 152
b2 = 289 – 225
b = ![C:thlbcrtzPYTHAGORAS_THEOREM_F2_filesimage021.gif](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIyOCIgaGVpZ2h0PSIyNCIgdmlld0JveD0iMCAwIDI4IDI0Ij48cmVjdCB3aWR0aD0iMTAwJSIgaGVpZ2h0PSIxMDAlIiBzdHlsZT0iZmlsbDojY2ZkNGRiO2ZpbGwtb3BhY2l0eTogMC4xOyIvPjwvc3ZnPg==)
b = 8cm
∴ r2 = 82+ 82
r2 = 64 +64
r2 = 64 +64
∴ r =11.31cm
2. Given triangle ABC, where B = 900.Find the lengths of the sides which are not given
![C:thlbcrtz__i__images__i__497.jpg](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxOTgiIGhlaWdodD0iMjMiIHZpZXdCb3g9IjAgMCAxOTggMjMiPjxyZWN0IHdpZHRoPSIxMDAlIiBoZWlnaHQ9IjEwMCUiIHN0eWxlPSJmaWxsOiNjZmQ0ZGI7ZmlsbC1vcGFjaXR5OiAwLjE7Ii8+PC9zdmc+)
3. A man travels 15km due north and then 8km due west. How far is he from his starting point?
Solution:
X2 = 152 +82
X2 = 225 +64
X = ![C:thlbcrtzPYTHAGORAS_THEOREM_F2_filesimage048.gif](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIzNyIgaGVpZ2h0PSIyNCIgdmlld0JveD0iMCAwIDM3IDI0Ij48cmVjdCB3aWR0aD0iMTAwJSIgaGVpZ2h0PSIxMDAlIiBzdHlsZT0iZmlsbDojY2ZkNGRiO2ZpbGwtb3BhY2l0eTogMC4xOyIvPjwvc3ZnPg==)
X = 17km
∴ He is 17km from his starting point
![C:thlbcrtz__i__images__i__D32.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIzNDIiIGhlaWdodD0iMzQiIHZpZXdCb3g9IjAgMCAzNDIgMzQiPjxyZWN0IHdpZHRoPSIxMDAlIiBoZWlnaHQ9IjEwMCUiIHN0eWxlPSJmaWxsOiNjZmQ0ZGI7ZmlsbC1vcGFjaXR5OiAwLjE7Ii8+PC9zdmc+)
Find the area of the triangle and the length of the perpendicular from C to B.
Solution:
![C:thlbcrtz__i__images__i__D7.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSI1NTIiIGhlaWdodD0iMTcxIiB2aWV3Qm94PSIwIDAgNTUyIDE3MSI+PHJlY3Qgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgc3R5bGU9ImZpbGw6I2NmZDRkYjtmaWxsLW9wYWNpdHk6IDAuMTsiLz48L3N2Zz4=)
![C:thlbcrtz__i__images__i__a11110.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxNDgiIGhlaWdodD0iMTQzIiB2aWV3Qm94PSIwIDAgMTQ4IDE0MyI+PHJlY3Qgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgc3R5bGU9ImZpbGw6I2NmZDRkYjtmaWxsLW9wYWNpdHk6IDAuMTsiLz48L3N2Zz4=)
![C:thlbcrtz__i__images__i__aaaa11.png](data:image/svg+xml;base64,PHN2ZyB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMjAwMC9zdmciIHdpZHRoPSIxMTQiIGhlaWdodD0iNzAiIHZpZXdCb3g9IjAgMCAxMTQgNzAiPjxyZWN0IHdpZHRoPSIxMDAlIiBoZWlnaHQ9IjEwMCUiIHN0eWxlPSJmaWxsOiNjZmQ0ZGI7ZmlsbC1vcGFjaXR5OiAwLjE7Ii8+PC9zdmc+)
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