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Scale Drawing Questions

 

1.  Three mountains Mikai, Kembo and Chaka in a village are situated in such a way that Kembo is 900m on a bearing of 1200 from Mikai. Mt. Chaka is 1200m on a bearing of 0300 from Kembo.

  1. Draw a sketch showing the position of the three mountains   (1 mk)
  2. Calculate the distance of Mt. Chaka from Mt. Mikai (2 mks)

2.  Shopping centres XY and Z are such that Y is 12km south of X and Z is 15kn from X. Z is on a bearing of N300W from Y. Calculate and give compass bearing of Z from X. (4mks)

3.  Four telephone posts PQR and S stand on a level ground such that Q is 28m on a bearing of 0600  from P. R is 20m to the south of Q and S is 16m on a bearing of 1400 from P.

 (a) Using a scale of 1cm represent 4m show the relative positions of the posts. (4mks)

 (b) Find the distance and bearing of R from S. (3mks)

 (c) If the height of post P is 15.6m. on a separate scale drawing, draw a diagram and determine the  angle of depression of post R from the top of post P. (3mks)

 (Same scale as above)

4.  Alice chepchumba on her cycling practice cycled on a bearing of 120o for 5.5km, then on a bearing of 200o for 8km finally he turned northwards for 13.5km, by scale drawing determine her final position from starting point. (4 marks)

5.  A surveyor recorded the measurement of field in a field book using lines AB = 260m as shown below.

 

B

 
 

130

R40

 

70

Q10

ecolebooks.com
 

50

P20

S50

10

 
 

A

 

 a) Use a suitable scale to draw the map of the field. (2 marks)

 b) Find the area of the field. (2 marks)

6. (a) In a Safari rally drivers are to follow route ABCGA. B is 250km from A on a bearing of 0750
from A. C is on a bearing of 1100 from A and 280km from B. the bearing of C from D is 1400 and at a distance of 300km. By scale drawing, show the position of the point A, B, C and D. (4 mks)

 (b) Determine

 (i) Distance of A from C (2 mks)

 (ii) The bearing of B from C  (1 mk)

 (iii) The distance and bearing of A from D (3 mks)

7.  Town X is 20km in the direction 060o from Y and Z is 30km in the direction 150o from Y. Using the scale 1cm represents 5km, find by scale drawing;

 (a)  the bearing of Y from Z

 (b)  the distance of X from Z (4mks)

8.  A field was surveyed and its measurements recorded in a field book as shown below.

 

 

E 40

 

C 40

F

100

80

60

40

20

A

 

 

 

D 50

 

B 30

 

(a) Using a scale of 1cm to represent 10m, draw a map of the field.  (4mks)

(b) Calculate the area of the field.

(i) in square metres.  (4mks)

(ii) in hectares.  (2mks)

9.  A plane leaves town P to town Q on a bearing of 1300 and a distance of 350km. it then flies to  town R 500km away and on a bearing 0600. Find by scale drawing the distance of R from P (3mks)

 

 

 

 

10.  A surveyor recorded the following information in his field book after taking measurements in  metres of a plot. The baseline is the straight line AH = 300m.

 

 

40 to F

120 to D

H

250

200

180

100

A

 

100 to G

 

80 to C

60 to B

 

(a) Using a scale of 1cm to represent 20m, draw an accurate diagram of the plot. (5mks)

b) Use your diagram to calculate the actual area of the field in hectares (5mks)

 

11.  Three town P,Q and R are such that P is on a bearing of 120° and 20 km from Q. Town R is on bearing of 220o and 12km from P

 a)  Using a scale of 1 cm to 2 km, draw and locate the positions of the three towns.  (3mks)

b)  Measure

i)  the distance between Q and R in kilometres. (2mks)  

ii)  the bearing of P from R.  (1mk)

iii)  the bearing of R from Q.  (2mks)

 c)  Calculate the area of the figure bounded by PQR. (2mks)

 

12.  The area of a forest on a map whose scale is 1:50,000 is 17cm2. Calculate the area of the forest in hectares. (2 mks)

13.  Four towns P, Q, R and S are such that town Q is 120km due east of town P. Town R is 160km due North of town Q. Town S is on a bearing of 330o from P and on a bearing 300 o from R. use a ruler and a pair of compasses only for all your constructions.

a)  Using a scale of 1cm to represent 50km, construct a scale drawing showing the positions P, Q, R and S. (6 mks)

b)  Use the scale to determine

  1. The distance from town S to town P. (1 mk)
  1. The distance from town S to town R. (1 mk)
  2. The bearing of town S from town Q. (2 mks)

14.  The actual area of an estate is 3510 hectares. The estate is represented by a rectangle measuring 2.6cm by 1.5cm on the map whose scale is l:n. Find the value of n  (3 mks)

15.  The following measurements were recorded in a field book of a farm in metres (xy = 400m)

 

 

C60

 

 

 

B 100

A 120

y

400

340

300

240

220

140

80

x

 

 

 

120 D

100 E

160 F

 a) Using a scale of 1cm representing 4000 cm, draw an accurate map of the farm.

 b) If the farm is on sale at Kshs.80,000.00 per hectare, find how much it costs.  (10 mks)

16.  Four points A, B, C and D are situated on a horizontal plane such that B is 250 m on a bearing of 0700 from A. C is 325 m on a bearing of 1500 from B. D is due west of C and on a bearing of 2100 from B.  (6 marks)

  1. Using a scale of 1 cm to 50 m draw an accurate drawing to show the position of A, B, C and D.
  2. Use your scale drawing fo find the :
    1. The distance between A and D (2 marks)
    2. The bearing of A from D (2 marks)

17.  Town X is 13.5km from town Y on a bearing of 028o. A matatu leaves y at 7:35a.m

towards a bearing of 080o. The matatu is at point Z due south of X at 8:55a.m

 (a) Calculate the average speed of the matatu from Y to Z

 (b) If the matatu continues on the same bearing, calculate the distance it covers from Z

when it is East of X  

18.  Three towns X, Y and Z are such that Y is 500km on a bearing of 315o from X. Z is on

a bearing of 230o from X. given that the distance between Y and Z is 800km.

 (a) using a scale of 1cm to represent 100km, draw a scale diagram to show the position

of the Towns  

 (b) Find the bearing of;

  (i) X from Z

  (ii) Z from Y  

 (c) Use the scale drawing to find the distance from X to Z

 

19.  Two aeroplanes S and R leave an airport at the same time. S flies on the bearing of 240o

at 750Km/h while R flies due East at 600Km/hr..

 (a) (i) Calculate the distance of each aeroplane after 30minutes  

  (ii) Using a scale of 1cm to represent 50km make an accurate scale drawing to show

the positions of the aeroplanes after 30minutes

 (b) (i) Use the scale drawing to find the distance between the two aeroplanes after 30minutes

  (ii) If each aeroplane landed after 30minutes and S received a signal to join R in 45minutes.

Find its speed  

 (c) Determine the bearing of :

  (i) S from R  

  (ii) R from S

 

20.  The table below gives a field book showing the results of a survey of a section of a piece of land

between A and E. All measurements are in metres.

 

D33

 

C21

B 42


 

E

95

90

70

30

25

A

 

 

F 36

 

G 25

H 40

 (a) Draw a sketch of the land.

 (b) Calculate the area of this piece of land.  

 

21. Three towns A B and C are situated such that town A is 40km from B on a bearing of 280o.

C is 60km from B on a bearing of 130o. Another town D is only 10km from C on a bearing of 210o.

(a) Drawing accurately and using a scale of 1cm to 10km find the:-

(b) Distance from A to C and the bearing of A from C

(c) (i) Distance of B from D

(ii) Distance of A from D

(iii) Bearing of A from D

(iv) Bearing of C from D

 

22.  A train left Naivasha for Nakuru at 1000hours. It traveled at an average speed of 45km/h

and reached Gilgil after 40minutes. It then covered the remaining 50km in 1½ hours. A second

train left Nakuru for Naivasha at 1015 hours and arrived at Gilgil at the same time as the first

train arrived at Nakuru.

 a) Using a scale of 1cm to represent 10minutes in the time axis and 1cm to represent 10km

on the distance axis, draw on the same axes the graphs to show the movement of the two

trains

b) use your graph to find;

  i) the distance between Naivasha and Nakuru

  ii) the time at which the train met

 c) calculate the average speed, in km/h of the second train

 

 

23.  On a certain map, a road 20km long is represented by a line 4cm long. Calculate the area

of a rectangular plot represented by dimensions 2.4cm by 1.5cm on this map – leaving

your answer in hectares

 

24.  A port B is on a bearings of 080o from a port A and at a distance of 95km. a submarine is

stationed at a port D, which is on a bearing of 200o from A, and a distance of 124km from B.

A ship leaves B and moves directly southwards to an island P, which is on a bearing of 140o

from A. the submarine at D on realizing that the ship was heading for the island P, decides to

head straight for the island to intercept the ship.

  (a) Using a scale of 1cm to represent 10km draw a diagram to show the positions of A,B,D, and P

 (b) Hence;

  Determine

  (i) the distance from A to D

  (ii) the bearing of the submarine from the ship when the ship was setting off from B  

  (iii) the bearing of the island P from D  

  (iv) the distance the submarine had to cover to reach the island P

 

25.  Use a scale of 1cm represents 50km in these questions. Five towns A, B, C, D and E are

situated such that A is 200 km from B on a bearing of 050° from E. C is 300 km from B on

a bearing of 150° from B. D is 350km on a bearing of 240° from C. E is 200km from D and the bearing of D from E is 100°

 a) Draw the diagram representing the positions of the towns

 b) From the diagram, determine;

  i) The distance in km of A from E

  ii) The bearing of D from B

 

26.  Four towns P, Q, R & S are such that P is 280 km North of R, S is190 km from R on a

bearing of 310o and Q is 240 km from P on a bearing of 105o.

a) Using scale of 1 cm rep. 50 km, locate the four towns.

b) Find; (i) distance SQ.  

(ii) Bearing of S from Q.

  (iii) The shortest distance between P and side QR.

 

27.  Four ships are at sea such that a streamliner S is 150km on a bearing of 025° from a cargo

ship C. A trawler T is 300km on a bearing of 145° from the cargo ship and a yacht Y is due

West of C and on a bearing of 300° from T.

 a) Using a scale of 1cm= 50km, draw on accurate scale drawing showing the positions of S, C, T

and Y

b) By measurement from your scale drawing determine:

 i) The distance and bearing of Y from S

 ii) The distance ST

 iii) The distance YT

 

28.  A tea farm in Kakamega forest was surveyed and the results were recorded in the surveyors

note book as shown below. The measurements are in meters

 

250

Y

 

C80

 

A60

240

170

70

50

D70

 

B60

X

0

 

Using a scale of 1: 25, draw the map of the plot and hence calculate the area of the plot in Hectares

 

 

29.  The information below shows the entries in a surveyor’s field book after a survey of a farm.

 XY = 280m is the baseline. All measurements are in metres

 

280

Y

B 105

 

 

A 100

230

190

160

90

40

110E

 

45E

 

95G

X

O

 

  (a) Use a scale of 1cm represents 20m to draw the map of the farm  

  (b) Estimate the area of the farm in hectares  

  (c) If the point Y lies due north of X, find correct to 1 decimal place, the :

  (i) Bearing of E from X

  (ii) Distance of E from X

 

30.  The measurements of a flower garden were recorded in a surveyor’s field book as shown.

 

250

Y

 

C80

240

170

70

D 70

 

B 60

X

0

 

Draw a sketch of the field and find its area. (Measurements are in m)

 

31.  A map has a scale 1:40,000:

 (a) Calculate the distance between two points on the ground if the corresponding distance

shown on the map is 3.25cm

 (b) Calculate the area in the map of woodland which occupies 36ha on the ground

32.  Three scouts John, Peter and Samwel stand on three adjacent peaks of equal altitude

on mountain range. The distance between John and Peter is 800metres and the bearing

of Peter from John is 020o. The distance between John and Samwel is 1500metres, and the

bearing of Samwel from John is 320o.

(a) Calculate the bearing of John from Peter  

(b) Calculate:- (i)
the distance

(ii) the bearing of Samwel from Peter

 

33.  The figure below represents a surveyor’s sketch of a plot of land. Calculate the area of the plot in

square metres given that XY = 50m, XK = 20m, XM = 25m, XL = 35m, KA = 40m, MD = 38m

and LB = YC = 60m.  

 

 

 

 

 

 

 

34.  Two boats P and Q are located 30km apart; P being due North of Q. An observer at P

spots a ship whose bearing he finds as S 56oE from Q, the bearing of the same ship is 038o. Calculate the distance of the ship from Q to 2 decimal places  

35.  A map is drawn to scale of 1:100,000. What area in km², is represented by a rectangle

measuring 4.5cm by 5.4 cm  

 

36.  Two places A and B are 900km apart on the earth’s surface. If A is due North of B and

given that the latitude of A is 5oN. Find the latitude of B. (Take radius of the earth to be 6370km)

37.  A car starts from rest and build up a speed of 40m/s in 1min 40seconds. It then travels

at this steady speed for 5minutes. Brakes are then applied and the car is brought to rest

in 2minutes.

 (a) Draw a velocity-time graph to show the journey

 (b) Use your graph to find;

  (i) the initial acceleration

  (ii) the deceleration when the car is brought to rest

(iii) the distance traveled

38.  The diagram below represents two vertical watch-towers AB and CD on a level ground.

 P and Q are two points on a straight road BD. The height of the tower AB is 20m and

road BD is 200m

 

 

 

 

 

 

 

 

 

 

 

 (a) A car moves from B towards D. At point P, the angle of depression of the car from

point A is 11.3o. Calculate the distance BP to 4 significant figures

 (b) If the car takes 5 seconds to move from P to Q at an average speed of 36km/.hr. Calculate

the angle of depression of Q from A to 2 decimal places

 (c) Given that QC = 50.9m, calculate;

(i) the height of CD in metres to 2 decimal places

  (ii) the angle of elevation of A from C to the nearest degree  

39.  Town B is 180 km on a bearing of 0500 from town A. Another town C is on a bearing of 1100

from town A and on a bearing of 1500 from town B. A fourth town D is 240 km on a bearing of

3200 from A. Without using a scale drawing, calculate to the nearest kilometer.

(a) The distance AC

  1. The distance CD

 

 

 

 

 

Scale drawing Answers

1

(i)

 

Image From EcoleBooks.com

(ii) MC Image From EcoleBooks.com

Image From EcoleBooks.com

 

 

B1

 

 

 

M1

 

 

 

A1

3

 

 

sketch not on scale

2.

Image From EcoleBooks.com

Image From EcoleBooks.com

Sin Z = 0.4

= 126.420

Compass bearing

N53.580W

 

 

 

 

 

 

 

 

 

 

M1

 

A1

M1

A1

 
  

04

 

3.

Image From EcoleBooks.com

Distance of R from S

 3.8cm 0.1

 3.8 x 4 = 15.2m

Bearing of R from S

 0680 10

 

Image From EcoleBooks.com

Angle of depression = 330

B1

 

B1

 

B1

 

B1

 

B1

B1

 

 

B1

 

 

 

 

B1

 

B1

 

 

 

B1

600 bearing from P and 7cm drawn

South of Q and 5cm drawn from P

1400 bearing from P and 4cm drawn

Completed diagram.

 

 

 

 

 

Award of 3 digits only

 

 

 

 

Posts P drawn

 

Position P and R shown and triangle completed

 

 

Angle of depression given

  

10

 

4

1cm represent 1km

 

 

 

N  D

 208o

4KM

 

120o

 

5.5km

 

B 200o

 

13.5km

 8KM

 

 C

 

 

Bearing 030o 4km from starting point

 

 

 

1M

 

 

 

 

1M

 

 

 

 

1M

 

 

 

 

A1

 

 

 

Bearing of starting point A

 

 

 

Use of scale correctly and plotting of points

 

 

Use of bearing correctly

5

  1. 1cm rep. 10m R

 

 P  d

 4cm

 B  Q  C

 A  1CM

A 1cm 4cm 2cm 6cm 3cm  B

F e

5cm

 

 

 

  1. Area

A = ½ x 5 x 2 = 5cm2

B = ½ X 2(2+ 1) = 3cm2

C = ½ x 6 (1+4) = 15cm2

D = ½ x 3 x 4 = 6cm

E= ½ x 5 x 15 = 75/2

= 37.5

 

f = ½ x 1 x 5 = 2.5

Total = 69cm2

 

Area = 69 x 1000000

10000

 

= 690m2

 

B1

 

 

B1

 

 

 

 

 

 

 

 

 

 

 

 

M1

 

 

 

 

 

 

A1

Correct scales

 

 

Correct drawing

7.

Image From EcoleBooks.com

 (a) 324o

 (b) (7.2 x 5)km

= 36km

 

 

B1

 

 

 

B1

 

 

 

 

 

B1

 

 

 

 

B1

 

 

Z accurately located wrt Y

 

 

X accurately located wrt Y

 

 

 

 

Bearing of X from Z

 

 

 

 

Distance of X from Z

  

04

 

8.

(a)

Image From EcoleBooks.com

(b) Area1 = ½ x 2 x 3 = 3cm2

Area2 = ½ x 4(5+3) = 16cm2

Area3 = ½ x 5 x 4 = 10cm2

Area4 = ½ x2x4 = 4cm2

Area5 = 4 x 4 = 16cm2

Area6 = ½ x 4 x 4 = 8cm2

Total area = (3+16+10+4+16+8)cm2

 = 57cm2

Actual area = (57×100)m2

 = 5700m2

(c) 10,000m2 = 1ha

5700m2 = ?

1 x 5700

10,000

= 0.57ha

 

 

 

S1

 

B1

 

B2

 

 

 

 

 

 

B1

 

 

B1

 

 

M1

 

 

A1

 

M1

 

A1

 

 

 

Scale

 

Base line

 

Offsets (all – offsets) A want B1 for at least 2

 

 

 

 

 

 

(3 areas)

 

 

(3 areas)

 

Addition of all six areas

  

10

 

9.

Image From EcoleBooks.com

B1

 

B1

 

 

 

 

 

 

B1

For North line at 600 may be simplified

lacation of R

 

 

 

 

 

 

for 700km  10km

  

03

 

10.

(a) Sin  = 8/12

DOC = 41.81 x 2

= 83.620

(b) Area of APCO = (16×20) – ( ½ x 122x sin 83.62)

 = 320 – 71.15

 = 248.45

(c) 83.62 x 22 x 122

360 7

 = 105.09cm2

(d) 248.45 – 105.09

 = 353.54

M1

M1

A1

M1

M1

A1

M1

 

A1

M1

A1

 
  

10

 

11.

Image From EcoleBooks.com

 

Image From EcoleBooks.com

 

B1

B1

B1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

M1A1

B1

B2

 

 

M1

 

 

A1

 

Locating Q

Locating P

Locating R

  

10

 

 

12.

 

1:50,000 L.S.F.

1:25,000,000 A.S.F.

17cm2: 425000000 cm2

42500 m2

 

42500

10,000

 

= 4.25 ha

 

 

 

M1

 

 

 

 

A1

2

 

13. Positions

 

Q  B1

R  B1

S  B1

 
 

 

 

 

 Const 300 B1

Image From EcoleBooks.com

  1. B1

 

Scale B1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

b.) i.  7.8 x 50 = 390 km. B1

ii.  7.10 x 50 = 355 km  B1

iii.  3200  B2

 

10

14.

Area = 35100000m2

= 351000000000cm2

Area = 2.6×1.5 = 3.9cm2

Scale = 3.9:351000000000

= 90000000000

 n = 9×1010

 

 

M1

 

A1

B1

 

 

 finding area

 

area (actual)

  

03

 

15.

Image From EcoleBooks.com

 

Areas.

Image From EcoleBooks.com

Total area = 62000m2 = 62000 = 6.2ha

10000

1ha = 80,000

6.2ha = 80000 x 6.2

1

= ksh 496,000.00

 

 

 

 

B3

 

 

 

 

 

 

 

 

 

M1

 

 

 

M1

 

 

 

M1

 

 

 

M1

 

 

B1

 

 

M

 

 

 

A1

 

 

 

 

3 for at least 6. 2 for at least 4, 1 for at least 2

  

10

 

 

 

16

Image From EcoleBooks.com

 

 

 

 

B1

 

 

B1

 

 

B1

 

 

B1

 

 

 

 

B1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

M1A1

M1A1

B1

 

 

 

 

 

 

 

 

 

 

 

Locating A

 

 

Locating B

 

 

Locating C

 

 

Locating D

 

 

 

 

North at D

 

 

 

10

 

 

17.  a)   YZ = 13.5

Sin 28o sin 100o

Duration of travel = 8:55a.m – 7.35a.m

= 4/3

Speed = 6.436

    4/3

   = 4.827km/hr

 

(b)  13.5 = 6.436 + ZQ

Sin 10o Sin 118o

6.436 + ZQ = 13.5 x sin118o= 68.659

ZQ= 68.659-6.436

= 62.223

 

18. 1cm rep 100km

Image From EcoleBooks.com

Image From EcoleBooks.com

 

b) i) 049  1

  ii) 190  1

c)  6.7 0.1

670  10

 

19.  a) (i) Distance covered by s

= (750 x ½ )km = 375 km

 

Image From EcoleBooks.com   Distance covered by R

= (600 x ½ ) km = 300 km

 

 
 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(b) (i) Distance between the two aeroplanes

  = 12.5 x 50  = 625 + 5 km

 

 

 (ii) Speed = 625 x 60 km/hr

45

= 833 1/3 km /h

 (c) (i) Bearing of S from R = 225o

  (ii) The bearing of R from S = 72o

 

20.  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 Area A: ½ x 25 (33 + 21) = 675

  Area B: ½ x 40 (21 x 42) = 1260

  Area C: ½ x 30 x 42 = 630

 Area D: ½ x 25 x 40 = 500

  Area E: ½ x 5 (40 + 25) = 162.5

  Area F: ½ X 60 (25 + 36) = 1830

 Area G: ½ x 5 x 36 = 90 √

= 5,147.5m2

 

21.  A to C = 96 ± 1 km

Bearing = 300o

 

  1. 62  1km
  2. 97  1 km
    1. 304o

030o

 

22.  Graph

 

b) i) 80 km

  ii) 11.06a.m

 

c) Average speed of the 2nd train

  Time taken = 80  111/12 = 80 x 12

23

= 41.74km/h

 

23.  L.S.F = 4 = 1

2000000 500000

A.S.F = 1
2 = 1

  5 x 105 2.5 x 1011

 

Area of rectangle = (2.4 x 1.5) cm2

 = 3.6cm2

Actual area = 3.6 x 2.5 x 1011 ha

100 x 10000

= 9 x 105

= 900,000ha

 

24.  a) Δ ABD  ly constructed

Δ ABP

  b) i) AD = 4.5 + 0.1cm

  Distance A + D

  = 4.5 X 10 = 45km

  ii) Bearing of (i) from B

  = 241 + 1

  iii) Bearing P from D

= 123 = 2

  iv) Dp = 12.9 + 0.2 am

 Distance D + P = 12.9 X 10

= 129 km

 

25. a)

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b) i)  6.8 + 0.1cm

Distance Ae = 340 + 5 km

 

ii) 180 + 18 = 198 + 2

 

26.  a)

Image From EcoleBooks.comImage From EcoleBooks.com

Image From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.com

 

 

 

b)  (i) SP = 7.8 x 50 = 390 km + 5 km

(ii) S & Q = 255o
+ 1o

(iii) 4 x 50 = 200 km + 5 km

 

 

 

27.  (a) Scale = 50km

Drawing accuratelyo

o

o

Lines drawn //

 

(b)By measurement:

(i) Distance SY = 6.9 x 50 = 345 5km

Bearing Y For S = 360o – 114 = 2461o

(ii) distance ST = 7.9 x 50 = 39.5 5km

  1. distance YT = 9.8 x 50 = 490 5km

 

 

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XY = 250m

Area of A = ½ x 50 x 60 = 1500m2

B = ½ x 70 x 60 = 2100m2

C = ½ (60 +80) x 120=11050m2

D = ½ x 80 x 80 = 3200m2

Image From EcoleBooks.comF = ½ x 10 x 70 = 350m2

Total area = 26600m2

Ha = 26600 = 2.66ha

10,000

29.

 

 

 

 

 

 

 

 

 

 

 

 

(b) Total area = area (1) + (2) + (3) + (4) +(5) + (6) + (7)

Area (1)= ½ x 90 x 100 = 4500m2

(2) = (100 + 105)10 = 10250m2

2

(3) = ½ x 90 x 105 = 4725m2

(4) = ½ x 50 x 110 = 2750m2

(5) = ½ x (110 + 45)70 = 5425m2

(6) = (45 + 95) 120 8400m2

  2

(7) = ½ x 40 x 95 = 1900m2

Total area = 37,950m2

In hectares = (37950) ha = 3.795ha

  10,000

(c) (i) bearing of E from x is 0.25  1o

`   (ii) Distance Ex = (12.8 0.1 x 20m) = 256  2m

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30.   Area  A = ½ x 170 x 80 = 6800

 B = ½ x 80 x 80 = 3200

C = ½ x 10 x 70 = 350

 D = ½ x 170 x 130 = 11050

E = ½ x 70 x 60 = 2100

Total = 23,500 m2

 

31.  (a)   L.s.f = 1

  40,000

1 = 3.25

40,000 x

  x = 130,000cm

 

(b) A.s.f = 1 2

40,000

1 2 = x

  40,000 36,000,000

 

x = 0.0225cm2

 

32.  

 

 

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(a) bearing = 180 + 20 = 200o

 

 

(b)  a2 = 1500 +

a2 = b2 + c2 – 2bc cos A

a2 = 15002 + 8002 – 2 x 1500 x 800cos 60

= 2250000 + 640000 – 1200000

= 1690000

a = 1300m

 

(c)  1300 = 1500

   Sin 60 sin c

1300 sin c = 1500 sin 60

  Sin c = 1500 sin 60

1300

  = 0.9993

c = 87.79o

c = 87.80

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33.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

.  A of ∆ XYD = ½ x 50 x 38 = 950m2

 A of XBCY = ½ (50 + 15) 60

= ½ x 65 x 60

= 1950m2

Total A = (950 + 1950)m2

= 2900m2

 

34.  B1 for 86o

30 = Q5

Sin 86o Sin 56o

QS = 30sin 56o

Sin 86o

= 24.93km

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35.  1cm for 100000cm

1cm2 = (100000cm)2

Area = 5.4 x 4.5 x 100000 cm2

= 5.4 x 4.5 x 100000 x 100000Km2

100000 x 100000

= 24.3km2

 

 

36.    x 22 x 6370 x 2 = 900

360 7

= 900 x 360 x 7

  22 x 6370 x 2

= 8.1o

Latitude of B = 8.1o – 5o N

= 3.5o S

 

Image From EcoleBooks.com37.  i) acc = 40 – 20

Image From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.comImage From EcoleBooks.com 100 – 50

= 20/50 = 0.4m/s

 

ii) 20 – 40 = -20

  460 – 400 60 = 0.3333 m/s2

 

iii) Area = ½ (520 + 300) x 40 x 1/1000 = 16.4 km

 

 

38.  a) Tan 11.3 = 200

  x

x = 200

  Tan 11.3 = 100.1m

 

b)  (36 x 1000) m/s

60 x 60

D = (10 x 5) 50m Tan  = 7.590

< of depression = 7.590

 

c) i) √ 50.92 – 49.92 = 10.04cm

  ii) Tan  = 10.04

200

 = 2.874°

= 3°

 

39.  a) Make a sketch to show positive of A, B, C and D

Image From EcoleBooks.com

 

Image From EcoleBooks.comImage From EcoleBooks.com

 

Image From EcoleBooks.com

 

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Image From EcoleBooks.com

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Use sine rule in ∆ABC


X
180
 x = 180 sin 80o

Sin 80o Sin 40o sin 40o

= 275.8

Hence AC = 276 km

 

(b) Use the cosine rule in ∆ AD when  DAC = 150o

y2 = 2402 + 2762 – 2 x 240 x 276 cos 150o

= 576000 + 76180 – 132 480 (-cos 30o)

= 133776 + 114731 = 248507

 

 y = 248507

 

  = 498.5

  Hence CD = 499 km

 

(c) Using sine rule in ∆ABC we have

   BC = 180

Sin 60o sin 40o

 

 BC = 180 sin 60

  Sin 40

 = 242.5

 = 243 km


 




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